How do I display the menu properly after each user input?

Question

I've been working on this all day and cannot figure out what I'm not understanding This simple program should ask for user input until they enter 9 and then the program exits.

There are 3 functions total. def main():, def menu():, and def menuInput():

1)def main():-simply calls menuInput

2)def menu():-displays a menu only

3)def menuInput():-calls the menu to be displayed, accepts user input, tests to make sure a valid number has been entered, Continues to ask the user for input until a valid choice is made, Repeats the menu selection until 9 is selected.

The problem is that the entire menu should be displayed, and then the program asks for the users selection 1-9. If 1 is chosen, it displays the message and shows the menu again, asking for the input.

Here is my code so far with comments based on my understanding or lack of

def main():
#calls menu input
  menuInput()

def menu():
#assigns the menu to menuDisplay
  menuDisplay = print('''
  Welcome! Please make a choice from the following menu

  1. Select a year and display available data
  2. Review averages by year range
  3. Select a date range to display highest
  4. Select a date range to display lowest 
  5. Get total for a selected year range
  6. blank
  7. blank
  8. See this menu again
  9. QUIT the program
''')


def menuInput():
#loops until 9 is selected  
while True:
    try:
      userChoice=int(input('Please make a selection: '))
    except ValueError:
    print('Please enter a whole number less than or equal to 9')

  if userChoice > 9:
    print('Please enter a number less or equal to 9')
  elif userChoice == 0:
    print('Please enter a number greater than 0')
  elif userChoice == 1:
    print('Good')
  elif userChoice == 2:
    print('Good')
  elif userChoice == 3:
    print('Good')
  elif userChoice == 4:
    print('Good')
  elif userChoice == 5:
    print('Good')
  elif userChoice == 6:
    print('Good')
  elif userChoice == 7:
    print('Invalid Choice')
  elif userChoice == 8:
    print('Good')
  else:
    print('Thank you! Program Exiting!')

#Calls main 
main()

Answer 1

def main():
#calls menu input
  menuInput()

def menu():
#assigns the menu to menuDisplay
  menuDisplay = print('''
  Welcome! Please make a choice from the following menu

  1. Select a year and display available data
  2. Review averages by year range
  3. Select a date range to display highest
  4. Select a date range to display lowest 
  5. Get total for a selected year range
  6. blank
  7. blank
  8. See this menu again
  9. QUIT the program
''')


def menuInput():
#loops until 9 is selected  
    while True:
        menu()
        try:
            userChoice=int(input('Please make a selection: '))
        except ValueError:
            print('Please enter a whole number less than or equal to 9')

        if userChoice > 9:
            print('Please enter a number less or equal to 9')
        elif userChoice == 0:
            print('Please enter a number greater than 0')
        elif userChoice == 1:
            print('Good')
        elif userChoice == 2:
            print('Good')
        elif userChoice == 3:
            print('Good')
        elif userChoice == 4:
            print('Good')
        elif userChoice == 5:
            print('Good')
        elif userChoice == 6:
            print('Good')
        elif userChoice == 7:
            print('Invalid Choice')
        elif userChoice == 8:
            print('Good')
        else:
            print('Thank you! Program Exiting!')
            exit(1)

#Calls main 
main()

You forgot to add exit(1)