CODEWITHSUNDEEP
xmlxsltxslt-2.0
xsltlife
xsltlife

Reputation: 163

Getting the position of an element in XSLT

I want to get the position of an element in XSLT.

Input:

<parent_root>
  <root>
    <ele>
      <fig/>
    </ele>
    <got/>
    <ele>
      <fig/>
    </ele>
    <got/>
    <got/>
    <ele>
      <fig/>
    </ele>
    <got/>
  </root>
</parent_root>

Output should be:

fig_1
fig_2
fig_3
fig_4

Tried code:

<xsl:template match="fig">
  <xsl:when test="parent::ele/following-sibling::got">
    <xsl:variable name="ID2" select="parent::ele/following-sibling::got/position()"/>
    <xsl:value-of select="concat('fig_','$ID2')"/>
  </xsl:when>
</xsl:template>

The error I am getting:

A sequence of more than one item is not allowed as the third argument of concat() (1, 2, ...)

How can I solve this? I am using XSLT 2.0. Thank you

Upvotes: 1

Views: 603

Answers (1)

zx485
zx485

Reputation: 29022

The position() function is relative to the current template, so it will always return 1 in your case. But you can easily achieve a similar function by counting the preceding <root> ancestor elements of your current <fig> element:

<xsl:template match="fig">
    <xsl:value-of select="concat('fig_',count(ancestor::root/preceding-sibling::root)+1,'&#xa;')" />
</xsl:template>

The last part of the concat() function, '&#xa;', is just there to provide the well formatted output of

fig_1
fig_2
fig_3

EDIT, because the question was changed:
To get all <got> elements and count all of its preceding <got> elements, you can use the following template:

<xsl:template match="got">
    <xsl:value-of select="concat('fig_',count(preceding::got)+1,'&#xa;')" />
</xsl:template>

Its output, which matches all <got> elements, is:

fig_1
fig_2
fig_3
fig_4

If you would match the <fig> elements, you would only get three nodes as output instead.

Upvotes: 2

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