Reputation: 6563
In my application, I have data returned from the server like below. It has very deep nesting:
var data = [{
name: "root",
children: [{
name: "Parent1",
children: [{
name: "Parent1-child1",
children: [{
name: "Parent1-child1-grandchild1",
children: [{
name: "Parent1-child1-grandchild1-last",
children:[]
}]
},
{
name: "Parent1-child1-grandchild2",
children: []
},
{
name: "Parent1-child1-grandchild3",
children: []
}
]
},
{
name: "Paren1-child2",
children: [{
name: "Parent1-chil2-grandchild1",
children: []
},
{
name: "Parent1-child2-grandchild2",
children: [{
name: "Parent1-child2-grandchild2-last",
children: []
}]
},
{
name: "Parent1-child2-grandchild3",
children: []
}
]
},
{
name: "Parent1-child3",
children: []
}
]
},
{
name: "Parent2",
children: [{
name: "Parent2-child1",
children: []
},
{
name: "Parent2-child2",
children: [{
name: "Parent2-child2-grandchild1",
children: []
},
{
name: "Parent2-child2-grandchild2",
children: [{
name: "Parent2-child2-grandchild2-last",
children: []
}]
}
]
}
]
},
{
name: "Parent3",
children: []
}
]
}];
The requirement is to loop through all the objects (deep nested level also) and remove the object if the children property has a value of an empty array. So the output should be like below
var data = [{
name: "root",
children: [{
name: "Parent1",
children: [{
name: "Parent1-child1",
children: [{
name: "Parent1-child1-grandchild1",
children: []
},
]
},
{
name: "Paren1-child2",
children: [
{
name: "Parent1-child2-grandchild2",
children: []
},
]
},
]
},
{
name: "Parent2",
children: [
{
name: "Parent2-child2",
children: [
{
name: "Parent2-child2-grandchild2",
children: []
}
]
}
]
}
]
}];
I have tried the following code, but it doesn't work as expected. Please let me know how to achieve the expected result.
function checkChildrens(arr) {
arr.forEach((ele,i) => {
if(ele.hasOwnProperty('children')) {
checkChildrens(ele['children'])
} else {
arr.splice(i,1)
}
})
}
checkChildrens(data);
I have tried with the filter method also in that case. It is not working correctly.
arr.filter((ele,i)=>{
if(ele.hasOwnProperty('children') && ele.children.length !== 0 ){
removeEmpty(ele.children)
}else{
return false;
}
return true;
})
Upvotes: 4
Views: 975
Reputation: 386560
You could rebuild new objects by checking the children array length.
function filter(array) {
return array.reduce((r, o) => {
if (o.children && o.children.length) {
r.push(Object.assign({}, o, { children: filter(o.children) }));
}
return r;
}, []);
}
var data = [{ name: "root", children: [{ name: "Parent1", children: [{ name: "Parent1-child1", children: [{ name: "Parent1-child1-grandchild1", children: [{ name: "Parent1-child1-grandchild1-last", children: [] }] }, { name: "Parent1-child1-grandchild2", children: [] }, { name: "Parent1-child1-grandchild3", children: [] }] }, { name: "Paren1-child2", children: [{ name: "Parent1-chil2-grandchild1", children: [] }, { name: "Parent1-child2-grandchild2", children: [{ name: "Parent1-child2-grandchild2-last", children: [] }] }, { name: "Parent1-child2-grandchild3", children: [] }] }, { name: "Parent1-child3", children: [] }] }, { name: "Parent2", children: [{ name: "Parent2-child1", children: [] }, { name: "Parent2-child2", children: [{ name: "Parent2-child2-grandchild1", children: [] }, { name: "Parent2-child2-grandchild2", children: [{ name: "Parent2-child2-grandchild2-last", children: [] }] }] }] }, { name: "Parent3", children: [] }] }],
result = filter(data);
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
Approach for removing all nested empty children (except the last one. This has an empty object, but no children property).
function filter(array) {
return array.reduce((r, o) => {
if (o.children) {
var children = filter(o.children);
if (children.length) r.push(Object.assign({}, o, { children }));
} else {
r.push(o);
}
return r;
}, []);
}
var data = [{ name: "root", children: [{ name: "Parent1", children: [{ name: "Parent1-child1", children: [{ name: "Parent1-child1-grandchild1", children: [{ name: "Parent1-child1-grandchild1-last", children: [] }] }, { name: "Parent1-child1-grandchild2", children: [] }, { name: "Parent1-child1-grandchild3", children: [] }] }, { name: "Paren1-child2", children: [{ name: "Parent1-chil2-grandchild1", children: [] }, { name: "Parent1-child2-grandchild2", children: [{ name: "Parent1-child2-grandchild2-last", children: [] }] }, { name: "Parent1-child2-grandchild3", children: [] }] }, { name: "Parent1-child3", children: [] }] }, { name: "Parent2", children: [{ name: "Parent2-child1", children: [] }, { name: "Parent2-child2", children: [{ name: "Parent2-child2-grandchild1", children: [] }, { name: "Parent2-child2-grandchild2", children: [{ name: "Parent2-child2-grandchild2-last", children: [] }] }] }] }, { name: "Parent3", children: [{}] }] }],
result = filter(data);
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
Upvotes: 5
Reputation: 11930
var data = [{
name: "root",
children: [{
name: "Parent1",
children: [{
name: "Parent1-child1",
children: [{
name: "Parent1-child1-grandchild1",
children: [{
name: "Parent1-child1-grandchild1-last",
children: []
}]
},
{
name: "Parent1-child1-grandchild2",
children: []
},
{
name: "Parent1-child1-grandchild3",
children: []
}
]
},
{
name: "Paren1-child2",
children: [{
name: "Parent1-chil2-grandchild1",
children: []
},
{
name: "Parent1-child2-grandchild2",
children: [{
name: "Parent1-child2-grandchild2-last",
children: []
}]
},
{
name: "Parent1-child2-grandchild3",
children: []
}
]
},
{
name: "Parent1-child3",
children: []
}
]
},
{
name: "Parent2",
children: [{
name: "Parent2-child1",
children: []
},
{
name: "Parent2-child2",
children: [{
name: "Parent2-child2-grandchild1",
children: []
},
{
name: "Parent2-child2-grandchild2",
children: [{
name: "Parent2-child2-grandchild2-last",
children: []
}]
}
]
}
]
},
{
name: "Parent3",
children: []
}
]
}];
function checkChildrens(arr) {
let res = []
arr.forEach(v => {
if (v.children && v.children.length) {
res = res.concat({
name: v.name,
children: checkChildrens(v.children)
})
}
})
return res
}
console.log(checkChildrens(data));
Upvotes: 1