CODEWITHSUNDEEP
javascript
Prakash Abhay
Prakash Abhay

Reputation: 35

Split a time range into pieces by other time ranges in javascript

I have a time range, for example: 14:30:00 until 18:30:00. Consider this time range somebody's work shift. During this time range, they state they cannot work from 15:30:00 until 16:30:00 and from 17:30:00 until 18:30:00.

var obj = {
startTime: 14:30,
endTime: 18:30
}

var deviation = [{s:15:30,e:16:30},{s:17:30,e:18:30}]

So i need output like 

[{s:14:30 ,e:15:30}, {s:15:30,e:16:30}, {s:16:30,e:17:30}, {s:17:30,e:18:30}]

Upvotes: 1

Views: 741

Answers (2)

Akshay Bande
Akshay Bande

Reputation: 2587

You can do it by concatenating your start time, end time with a sorted deviation array. Create an array from that concatenated array.

var obj = {

  startTime: '14:30',
  endTime: '18:30'
}

var deviation = [{s:'15:30',e:'16:30'},{s:'16:30',e:'18:30'}]

function intervals(obj,deviation){

  // sort deviation according to starting time of deviations
  deviation.sort((a,b)=>{
    return a.s < b.s ? -1 : 1 ;
  })

  if(deviation[0].s >= obj.startTime && deviation[deviation.length - 1].e <= obj.endTime){

    let ans = [];

    ans = deviation.reduce((acc,val)=>{
      return acc.concat( val.s, val.e);
    },[]);


    // check if starttime and minimum time deviation is not same.
    if(ans[0] != obj.startTime){

      ans.unshift(obj.startTime);	
    }

    // check if endtime and maximum time in deviation is not same.
    if(ans[ans.length - 1]!=obj.endTime){

      ans.push(obj.endTime);	
    }

    let temp = [];

    // create an array of objects from sorted list ans;
    for(let i = 0; i < ans.length; i++){

      if(i+1 < ans.length){
        if(ans[i]!=ans[i+1]){
          temp.push({
            s: ans[i],
            e: ans[i+1]
          });
        }
      }
    }
    return temp;
  }
  else{
    console.log("Invalid values of deviation.");					
  }
}

console.log(intervals(obj,deviation));

Upvotes: 1

Vinay Kaklotar
Vinay Kaklotar

Reputation: 424

I has created an example as you want. I think code is something tough and long so if it helpful for you then use otherwise ignore it.

    var obj = {
        s: '14:30',
        e: '18:30'
    }
    var deviation = [{
            s: '15:30',
            e: '16:30'
        },
        {
            s: '17:30',
            e: '18:30'
        }]

    $(document).ready(function () {
        deviation.push(obj);
        var newArr = [];
        $(deviation).each(function (index, value) {
            newArr.push(value.e);
            newArr.push(value.s);
        });
        var newArr = newArr.sort();
        var $timeArr = [];
        lastVal = '';
        $(newArr).each(function (index, value) {

            if (index == 0) {
                lastVal = value;
            } else {
                var stTime = lastVal;
                var endTime = value;

                lastVal = endTime;
                var pushObj = {
                    s: stTime,
                    e: endTime
                }
                var lsstKey = newArr.length - 1;
                if (index != lsstKey) {
                    $timeArr.push(pushObj);
                }
            }
        });
  			document.getElementById("myarray").innerHTML = JSON.stringify($timeArr);
    });
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<p id="myarray"></p>

Please check in below link

https://jsfiddle.net/vinay_kaklotar/vbt1uspe/3/

Upvotes: 2

Related Questions