CODEWITHSUNDEEP
python
Wagner Ideali
Wagner Ideali

Reputation: 41

Multiple labels with different names in a frame for python

I am new in python and a need to have in my solution multiple labels. My solution was below. Somebody has a better solution for this? I need 20 labels. 

            if pos_x == 1:
                lb1 = Label(janela, text=data[rabo], font="arial 18")
                lb1.grid(row=pos_x, column=pos_y, padx=2, pady=2)
            if pos_x == 2:
                lb2 = Label(janela, text=data[rabo], font="arial 18")
                lb2.grid(row=pos_x, column=pos_y, padx=2, pady=2)
            if pos_x == 3:
                lb3 = Label(janela, text=data[rabo], font="arial 18")
                lb3.grid(row=pos_x, column=pos_y, padx=2, pady=2)
            if pos_x == 4:
                lb4 = Label(janela, text=data[rabo], font="arial 18")
                lb4.grid(row=pos_x, column=pos_y, padx=2, pady=2)
            if pos_x == 5:
                lb5 = Label(janela, text=data[rabo], font="arial 18")
                lb5.grid(row=pos_x, column=Pos_y, padx=2, pady=2)

Upvotes: 0

Views: 185

Answers (2)

ArunJose
ArunJose

Reputation: 2159

use 

if pos_x == i:
    lb[i] = Label(janela, text=data[rabo], font="arial 18")              
    lb[i].grid(row=pos_x, column=pos_y, padx=2, pady=2)

Upvotes: 0

George Shuklin
George Shuklin

Reputation: 7887

Using lb1,...,lb5 (up to lb20) is looking strange to me. They are almost (?) identical, so I would suggest to use a list:

lb = [None] * number_of_lb  # make array of 20 None
...
lb[pos_x] = Label(..)
lb[pos_x].grid = ...

Later you can access them as lb[0], lb[1], etc.

Upvotes: 1

Related Questions