Reputation: 187
I have a dataframe where I want to sum up all "Hours" (column header) into "total sum" for each "Name" (column header) under 1 "Manager" (column header). I then want to drop all duplicates before sorting the the dataframe based on the total hours sum and print out row by row. However I keep getting duplicates of the Manager row by row print out?
|---------------------|------------------|---------------------|------------------|
| Department | Name | Manager | Hours |
|---------------------|------------------|---------------------|------------------|
| Department name | person Name | Manager Name |no of hours |
|---------------------|------------------|---------------------|------------------|
def total_group(csv_file):
df = pd.read_csv(csv_file)
df['Total Hours'] = df.groupby(['Manager'])['Hours'].transform('sum')
new_df = df.drop_duplicates(subset=['Department', 'name', 'Manager']).sort_values('Total Hours')
for index, row in new_df.iterrows():
manager_value = row['Manager']
total_hours = row['Total Hours']
print("manager: {}, has: {} Total hours".format(manager_value, total_hours))
print(total_group(csv_file))
Dataframe print
df1 = df['Total Hours'] = df.groupby(['Direct Manager'])['Labor Hours'].transform('sum')
print(df1)
result
0 450.0
1 450.0
2 450.0
3 450.0
4 450.0
...
43929 320.5
43930 320.5
43931 320.5
43932 320.5
43933 320.5
Name: Hours, Length: 43934, dtype: float64
new dataframe print:
new_df = df.drop_duplicates(subset=['Department', 'Direct Manager']).sort_values('Total Hours')
print(new_df)
Result:
Department Name Hours Total Hours
9554 Europe Dri, Bas ... 8.0 72.000000
34498 Product & Design Sun, Sunn ... 5.0 81.000000
19140 Product & Design Oers, Len ... 8.0 122.000000
what I would like is a dataframe like this:
Department Manager Total Hours
9554 Europe Last, First ... 72.000000
34498 Product Last, first ... 81.000000
19140 Design Last, First ... 122.000000
Upvotes: 0
Views: 168
Reputation: 172
Do you want to try this
df.groupby('Manager').agg({'Hours':['sum','count']}).sort_values(('Hours','sum'), ascending=False)
Upvotes: 1