CODEWITHSUNDEEP
pythonregexgrep
joedborg
joedborg

Reputation: 18353

Finding a line in a Python string (not file)

I know how to do this with a file, you just do file = file.open(f) f

file = open("file.txt")
for line in file.readlines():
  if line.startswith("foo"):
    print line

But now I'm reading the output of a process like this

log = os.popen("log.sh").read()

This outputs as a string, which can be used with print fine, but if I do a "for line in log" it splits each character, not line. And, being a string, there is no .readlines() attribute.

My end goal is to be able to "grep" for a revision number in the log and print the line (and above and below)

Upvotes: 1

Views: 3729

Answers (2)

NPE
NPE

Reputation: 500437

You have several options:

Option 1:

log = os.popen("log.sh").readlines()

This gives a list of string that you can process exactly like you do when reading a file.

Option 2:

log = os.popen("log.sh").read()
for line in log.splitlines(True):
   ...

Upvotes: 6

Sven Marnach
Sven Marnach

Reputation: 601789

for line in log.splitlines():
    # whatever

Note that you don't need to use f.readlines() for a file f.

for line in f:
    # whatever

will work fine.

Upvotes: 9

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