CODEWITHSUNDEEP
pythondjangocommand
JokerPy
JokerPy

Reputation: 53

python django create own command and add list as parameter

I want to use py manage.py own_command.

I got the following code:

from django.core.management.base import BaseCommand


class Command(BaseCommand):
    help = 'create user'

    def add_arguments(self, parser):
        parser.add_argument('--username', type=str, help='set username')
        parser.add_argument('--password', type=str, help='set password')
        parser.add_argument('--email', type=str, help='set password')
        parser.add_argument('--group', type=list, default=[], action='append', help='set group(s) like ["basic", "advanced"]')
        parser.add_argument('--permission', type=list, default=[], action='append', help='set permission(s) like ["delete", "write"]')


>py manage.py create_app_user --username dustin --password hdf --email "" --group ["admin", "basic"
]

creates

usage: manage.py create_app_user [-h] [--username USERNAME]
                                 [--password PASSWORD] [--email EMAIL]
                                 [--group GROUP] [--permission PERMISSION]
                                 [--version] [-v {0,1,2,3}]
                                 [--settings SETTINGS]
                                 [--pythonpath PYTHONPATH] [--traceback]
                                 [--no-color]
manage.py create_app_user: error: unrecognized arguments: basic

]

I found solutions for django <= 1.7 BUT not for >=2.1

Upvotes: 4

Views: 1858

Answers (1)

bug
bug

Reputation: 4130

You only need to specify either nargs='*', to allow 0 or more values, or nargs='+' to allow 1 or more values, eg:

parser.add_argument(
    '--group',
    nargs='*',
    help='set group(s) like "basic", "advanced"',
)

Also, you need to call your command without square brackets or commas:

py manage.py create_app_user --username dustin --password hdf --email "" --group "admin" "basic"

Upvotes: 8

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