CODEWITHSUNDEEP
python
BeR
BeR

Reputation: 61

How to obtain user input in Python?

I would like to learn how to code this.

Here is how I want it to look

Do you want strawberry ice cream? (y:n) n
Do you want chocolate ice cream?  (y:n) y
Do you want mint ice cream? (y:n) n
Do you want vanilla ice cream? (y:n) y

then the output would be: Here is your ice cream. or if you put N to all, You did not say yes to any. Or with the else statement: I didn't get that, try again.

Any help is very much appreciated, thank you.

My test script:

def kind(chosenIce):
      chosenIce=input("Do you want a ice cream (y:n) ")
      if chosenIce1 == 'y':
          ice1 = print("message")
      if chosenIce2 == 'y':
          ice2 = print("message")
      if chosenIce1 == 'n':
          ice1 = 0
      if chosenIce2 == 'n':
          ice2 = 0
      else:
         print("Sorry, I did not get that. Try again.")
kind(chosenIce)

Upvotes: 0

Views: 229

Answers (4)

ZF007
ZF007

Reputation: 3741

In python 3 you can use input() (examples here) and in python 2 raw_input() (examples here). You need to code the rest yourself using for-loops... etc.

Example:

choices = []

x1 = input('Do you want strawberry ice cream? (y/n)')

choices.append(x1)  # store the choice for each question here so you can use it later for
                # selection criteria process. Store x2 at choices[1], etc.

for choice in choices:
    if choice in ['y', 'Y', 'yes', YES']:
        print ('User does like an iscream')
    else:
        print ('User no fan of the cold treat')

Upvotes: 0

SRG
SRG

Reputation: 345

listQue=["Do you want strawberry ice cream?","Do you want chocolate ice cream?","Do 
you want mint ice cream?","Do you want vanilla ice cream?"]

flag=False
for que in listQue:
    ans=input(que)
    if(ans=='Y'):
        res=que.split()
        print("Here is your"," ".join(res[3:6]).rstrip('?'))
        flag=True
   else:
        pass


if(flag==False):
    print("Ohhh sorry you didn't choose anything")

Upvotes: 1

codrelphi
codrelphi

Reputation: 1065

As some fellows said, you have to use input and loop (i.e for loop or while loop) to achieve your goal. By reading your post and the comments, it seems you are really a newbie in Python. So, below, I give you a basic workflow that does something like your needs. There are many ways to achieve your goals. You can look at my workflow for inspiration.

Here is the code:

def kind(ices_cream):
    choices = []
    for ice in ices_cream:
        chosenIce = input('Do you want "{}" ice cream (y:n) '.format(ice))
        if chosenIce == 'y':
            choices.append(ice)
        elif chosenIce == 'n':
            print("You refuse ", ice)
        else:
            print("Sorry, I did not get that. Try again.")

    if len(choices):
        print("\n", "You buy", ' and '.join(choices))
    else:
        print("\n", "You buy nothing!")

if __name__ == "__main__":
    ices_cream = ["Chocolate", "Strawberry", "Mint", "Vanilla"]
    kind(ices_cream)

Outputs: It is an example

Do you want "Chocolate" ice cream (y:n) y
Do you want "Strawberry" ice cream (y:n) n
You refuse  Strawberry
Do you want "Mint" ice cream (y:n) y
Do you want "Vanilla" ice cream (y:n) n
You refuse  Vanilla

 You buy Chocolate and Mint

NB: You can add a loop while to force the user to input the characters y or n. Also, you can add exception handling if you want to do a good job.

Upvotes: 1

Bogdan Doicin
Bogdan Doicin

Reputation: 2416

Regarding only what you want in this problem, you will use the function input. The way to use it is this:

strawberryIceCream=input('Do you want strawberry ice cream? (y/n)')

and so on, so forth with the other options as well. Remember to store each option in either a different variable or, better IMHO, in a set or tuple.

Further info on input

However, the comments' on your question are accurate and on point. This is why I mentioned that this answer will answer only your question. Nothing more, nothing less.

Upvotes: 1

Related Questions