CODEWITHSUNDEEP
phplaravel
Tanvir Ahmed
Tanvir Ahmed

Reputation: 1019

How to solve array push problem in laravel

i have a Two fields 1. allowances which is contain this data

{"medical":"600","transport":"350","food":"900"}

and another one 2. house rent which is contain this data 

2550.00

now i want to get a result in third column like this

{"medical":"600","transport":"350","food":"900","house_rent":"2550.00"}

so far i tried this 

$allowances=json_decode($salary->allowances);
$house_rent = array('House Rent' => $salary->house_rent);
$allowances_logs=array_push($allowances,$house_rent);
$salary->allowances_logs = $allowances_logs;

but it gives me following error"array_push() expects parameter 1 to be array, object given". Help me achieve this result. Any help will be appreciated

Upvotes: 0

Views: 91

Answers (3)

BCM
BCM

Reputation: 675

First convert your json to array. You can do this with json_decode php function.

json_decode function convert your json to object or associative array. First argument on this function is the json string being decoded. When is second argument are TRUE, returned objects will be converted into associative arrays.

$testJson = '{"medical":"600","transport":"350","food":"900"}';
$testArr = json_decode($testJson, true);

Output - Array ( [medical] => 600 [transport] => 350 [food] => 900 )

Now you can add new item to your array.

$testArr['house_rent'] = '2550.00';

Your array now look like this.

Array ([medical] => 600 [transport] => 350 [food] => 900 [house_rent] => 2500.00)

At the end you convert your array to json. For this you can use php json_encode function.

$testJson = json_encode($testArr);

Full Example

$testJson = '{"medical":"600","transport":"350","food":"900"}';
$testArr = json_decode($testJson, true);

$testArr['house_rent'] = '2500.00';

$testJson = json_encode($testArr);
echo $testJson;

Upvotes: 0

Sagar Patel
Sagar Patel

Reputation: 414

true Add second argument in json_decode(), so you can see below example

$mainArr = json_decode('{"medical":"600","transport":"350","food":"900"}',true);
$house_rent = array('House Rent' => 2550.00);
$printArr = array_merge($mainArr, $house_rent);
print_r(json_encode($printArr));

Output

{"medical":"600","transport":"350","food":"900","House Rent":2550}

Upvotes: 0

jotaelesalinas
jotaelesalinas

Reputation: 1497

First, add true as second argument to json_decode(), and you will retrieve the results as an array instead of an object.

Second, with the two arrays, do:

$merged = array_merge($arr1, $arr2);

Upvotes: 1

Related Questions