CODEWITHSUNDEEP
c#linq-to-xml
Doug
Doug

Reputation: 264

Path of Current Node in XDocument

Is it possible to get the path of the current XElement in an XDocument? For example, if I'm iterating over the nodes in a document is there some way I can get the path of that node (XElement) so that it returns something like \root\item\child\currentnode ?

Upvotes: 6

Views: 5196

Answers (3)

donatasj87
donatasj87

Reputation: 900

I know the question is old, but in case someone wants to get a simple one liner:

XElement element = GetXElement();
var xpath = string.Join ("/", element.AncestorsAndSelf().Reverse().Select(a => a.Name.LocalName).ToArray());

Usings:

using System.Linq;
using System.Xml.Linq;

Upvotes: 2

Alexei Levenkov
Alexei Levenkov

Reputation: 100545

Depending on how you want to use the XPath. In either case you'll need to walk tree up yourself and build XPath on the way.

If you want to have readable string for dispaly - just joining names of prent nodes (see BrokenGlass suggestion) works fine

If you want select later on the XPath

  • positional XPath (specify position of each node in its parent) is one option (something like //[3]/*). You need to consider attributes as special case as there is no order defined on attributes
  • XPath with pre-defined prefixes (namespace to prefix need to be stored separately) - /my:root/my:child[3]/o:prop1/@t:attr3
  • XPath with inlined namespaces when you want semi-readable and portable XPath /*[name()='root' & namespace-uri()='http://my.namespace']/.... (see specification for name and namespace-uri functions http://www.w3.org/TR/xpath/#function-namespace-uri)

Note that special nodes like comments and processing instructions may need to be taken into account if you want truly generic version of the XPath to a node inside XML.

Upvotes: 1

BrokenGlass
BrokenGlass

Reputation: 160942

There's nothing built in, but you could write your own extension method:

public static string GetPath(this XElement node)
{
    string path = node.Name.ToString();
    XElement currentNode = node;
    while (currentNode.Parent != null)
    {
        currentNode = currentNode.Parent;
        path = currentNode.Name.ToString() + @"\" + path;
    }
    return path;
}


XElement node = ..
string path = node.GetPath();

This doesn't account for the position of the element within its peer group though.

Upvotes: 4

Related Questions