CODEWITHSUNDEEP
cpointers
Prince Kumar Singh
Prince Kumar Singh

Reputation: 29

How do I loop over a char pointer in C?

I am trying to access all elements of this preinitialized char pointer in 'c'. Here is the code:

#include <stdio.h>
#include <stdlib.h>

void main()
{
    char **s="Hello";
    printf("%c",*(*&s+1));
}

This code should output "e", but doesn't. What am I doing wrong?

Also, how do I access all elements one by one?

Upvotes: 0

Views: 470

Answers (2)

JiHo Han
JiHo Han

Reputation: 31

Assumed that you are not seeing the 'e' of the Hello, I highly recommend watching this post.

What to do when the pointer doesn't print the string properly

Just to summarize, when you reference the pointer s, it is only reading the H of Hello (since that is how the pointer of string works - it points to the first character of the string, like s[0]), and that results your code in printing out H only.

Most importantly, your pointer is double-pointer, which is incorrect.

Try it in this way.

#include <stdio.h>
#include <stdlib.h>
void main()
{
  char s[] = "Hello";
  printf("%s\n",s);
}

Upvotes: 0

dbush
dbush

Reputation: 223699

The type of s is incorrect. The string constant "Hello" has array type which can decay to type char * but you're assigning it to a variable of type char **.

Change the type of s to char * and your code will output "e":

 char *s = "Hello";

Also, looking at this:

*(*&s+1)

When * comes right before & they cancel each other out. So you can simplify this to:

*(s+1)

Or equivalently:

s[1]

Upvotes: 3

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