Reputation: 83
Say I have an array [10000,5000,1000,1000] and I would like to find the closest sum of numbers to a given number. Sorry for the bad explanation but here's an example:
Say I have an array [10000,5000,1000,1000] I want to find the closest numbers to, say 6000.
Then the method should return 5000 and 1000
another example : we want the closest to 14000 , so then he should return 10000 and 5000
I've tried with code below, here is working one but if the $desiredSum and $numbers array is big. it's running so slow until php execution timeout
$numbers = array(
10000,5000,1000,1000
);
$desiredSum = 6000;
$minDist = null;
$minDist_I = null;
// Iterate on every possible combination
$maxI = pow(2,sizeof($numbers));
for($i=0;$i<$maxI;$i++) {
if(!(($i+1) % 1000)) echo ".";
// Figure out which numbers to select in this
$sum = 0;
for($j=0;$j<sizeof($numbers);$j++) {
if($i & (1 << $j)) {
$sum += $numbers[$j];
}
}
$diff = abs($sum - $desiredSum);
if($minDist_I === null || $diff < $minDist) {
$minDist_I = $i;
$minDist = $diff;
}
if($diff == 0) break;
}
$chosen = array();
for($j=0;$j<sizeof($numbers);$j++) {
if($minDist_I & (1 << $j)) $chosen[] = $numbers[$j];
}
echo "\nThese numbers sum to " . array_sum($chosen) . " (closest to $desiredSum): ";
echo implode(", ", $chosen);
echo "\n";
Anyone can help me out ?
Upvotes: 1
Views: 707
Reputation: 17805
<?php
function coinChange($numbers,$desiredSum){
sort($numbers);
$set = [];
$set[0] = [];
for($i = $numbers[0];$i <= $desiredSum;++$i){
foreach($numbers as $index => $current_number){
if($i >= $current_number && isset($set[$i - $current_number])){
if(isset($set[$i - $current_number][$index])) continue;
$set[$i] = $set[$i - $current_number];
$set[$i][$index] = true;
break;
}
}
}
if(count($set) === 0){
return [0,[]];
}
if(isset($set[$desiredSum])){
return [
$desiredSum,
formatResult($numbers,array_keys($set[$desiredSum]))
];
}else{
$keys = array_keys($set);
$nearestSum = end($keys);
$sum = 0;
$rev_numbers = array_reverse($numbers);
$result = [];
foreach($rev_numbers as $number){
$sum += $number;
$result[] = $number;
if($sum > $nearestSum && abs($nearestSum - $desiredSum) > abs($sum - $desiredSum)){
$nearestSum = $sum;
break;
}else if($sum > $nearestSum && abs($nearestSum - $desiredSum) < abs($sum - $desiredSum)){
$result = formatResult($numbers,array_keys($set[$nearestSum]));
break;
}
}
return [
$nearestSum,
$result
];
}
}
function formatResult($numbers,$keys){
$result = [];
foreach($keys as $key) $result[] = $numbers[$key];
return $result;
}
print_r(coinChange([10000,5000,1000,1000],14000));
print_r(coinChange([10000,5000,1000,1000],13000));
print_r(coinChange([100000,100000,100000,100000,100000,100000,50000,50000,50000,50000,10000,10000,500,500,500,1000,1000],250000));
print_r(coinChange([100000,100000,100000,100000,100000,100000,50000,50000,50000,50000,10000,10000,500,500,500,1000,1000],179999));
Demo: https://3v4l.org/hBGeW
Algorithm:
This is similar to coin change problem.
We first sort the numbers.
$i
(which is a sum) only if we have made sum $i - $current_number
. If we have the previous one, then we add $current_number
to our collection for sum $i
.Two Scenarios:
$set
which would be the last entry. We keep them in a variable.Result format:
Let's take the below sample output:
Array
(
[0] => 15000
[1] => Array
(
[0] => 10000
[1] => 5000
)
)
It simply means that the first index is the nearest sum possible and array at 2nd index is all elements it took from $numbers
to make that sum.
Upvotes: 2