CODEWITHSUNDEEP
pythonpython-3.xtkinter
Hana
Hana

Reputation: 5

Python - How to change the color of one button in a list of buttons

I'm trying to change the color of a button. Here is the code.

for i in range(6):
    for j in range (6):
        if i == 0 and j == 0:
            grids6 = tk.Button(mFrame, bg='blue', highlightcolor="black", highlightthickness=1, state = "disabled", width = 11, height = 5)
             grids6.grid(row = i, column = j)
        elif i == 5 and j == 5:
            grids6 = tk.Button(mFrame, bg='red', highlightcolor="black", highlightthickness=1, state = "disabled", width = 11, height = 5)
            grids6.grid(row = i, column = j)
        else:
            grids6 = tk.Button(mFrame, bg='black', highlightcolor="black", highlightthickness=1, state = "disabled", width = 11, height = 5)
            grids6.grid(row = i, column = j)
grids6[(3,4)].configure(background= 'red') # here is where I tried to change the color but with no success

Upvotes: 0

Views: 189

Answers (1)

stovfl
stovfl

Reputation: 15513

Question: How to access one Button in a grid of Button.

Using .grid(row=i, column=j) you layout widgets in a Row/Column manner.
To access, one of the widget later on, you can use grid_slaves(row=None, column=None).

This implements a OOP solution, to get your initial approach to work:

mFrame[(3,4)].config(bg= 'red')

class Board(tk.Frame):
    def __init__(self, parent, **kwargs):
        super().__init__(parent, **kwargs)

    def __getitem__(self, coord):
        if isinstance(coord, tuple):
            return self.grid_slaves(row=coord[0], column=coord[1])[0]


class Square(tk.Button):
    def __init__(self, parent, **kwargs):
        # Defaults
        kwargs['highlightcolor'] = "black"
        kwargs['highlightthickness'] = 1
        kwargs['state'] = "disabled"
        kwargs['width'] = 11
        kwargs['height'] = 5
        super().__init__(parent, **kwargs)

Usage 

class App(tk.Tk):
    def __init__(self):
        super().__init__()
        self.geometry("800x600")

        board = Board(self)
        board.grid()

        for row in range(6):
            for column in range(6):
                if row == 0 and column == 0:
                    square = Square(board, bg='blue', )
                elif row == 5 and column == 5:
                    square = Square(board, bg='red', )
                else:
                    square = Square(board, bg='black', )

                square.grid(row=row, column=column)

        # Access the Square in Row index 3 and Column index 4,
        # using subscript the object `board` by `(3, 4)`.
        board[(3, 4)].configure(bg='red')

        # Extend, `class Board` to acces the first Square with (1, 1)
        # Allow only >= (1, 1) ans subtract 1
        # Or Layout Row/Column >= 1, 1
        # board[(1, 1)].configure(bg='yellow')


if __name__ == '__main__':
    App().mainloop()

Tested with Python: 3.5 - 'TclVersion': 8.6 'TkVersion': 8.6

Note: This will not work on MACOS, there you can't change the Background color of tk.Button. Replace tk.Button with tk.Canvas.

Upvotes: 1

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