CODEWITHSUNDEEP
python
Jananath Banuka
Jananath Banuka

Reputation: 633

Unknown shorthand flag: 'E' in -E

I am trying to execute a bash command in python

The bash command I want to execute is: kubectl get ns | grep -E '(^|\s)OK($|\s)'

And in python I do this like this:

is_namespace_exists = subprocess.call(["kubectl", "get", "ns", "|", "grep", "-E", "\'(^|\s)"+NAMESPACE+"($|\s)\'"])

and

is_namespace_exists = subprocess.call(["kubectl", "get", "ns", "|", "grep", "-E", "'(^|\s)"+NAMESPACE+"($|\s)'"])

But I get this error:

unknown shorthand flag: 'E' in -E

Can someone tell me what is going wrong?

Upvotes: 0

Views: 2542

Answers (1)

user8246956
user8246956

Reputation:

The following code should work:

import subprocess

NAMESPACE = "..."  # Define NAMESPACE variable here

proc1 = subprocess.Popen(['kubectl', 'get', 'ns'], stdout=subprocess.PIPE)
proc2 = subprocess.Popen(["grep", "-E", "\'(^|\s)"+NAMESPACE+"($|\s)\'"], stdin=proc1.stdout, stdout=subprocess.PIPE, stderr=subprocess.PIPE)

proc1.stdout.close() # Allow proc1 to receive a SIGPIPE if proc2 exits.
out, err = proc2.communicate()
print('out: {0}'.format(out))
print('err: {0}'.format(err))

Basically an adaptation of this post. Adapt according to your needs.

Upvotes: 2

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