CODEWITHSUNDEEP
javascriptarraysnumbers
Alistair Tsang
Alistair Tsang

Reputation: 11

returns [] when passed an empty string and returns the lengths when passed multiple words

so i need to write a function that gets the length of each individual words on the array that will pass these conditions 

it("returns [] when passed an empty string", () => {
    expect(getWordLengths("")).to.eql([]);
  });
  it("returns an array containing the length of a single word", () => {
    expect(getWordLengths("woooo")).to.eql([5]);
  });
  it("returns the lengths when passed multiple words", () => {
    expect(getWordLengths("hello world")).to.eql([5, 5]);
  });
  it("returns lengths for longer sentences", () => {
    expect(getWordLengths("like a bridge over troubled water")).to.eql([
      4,
      1,
      6,
      4,
      8,
      5
    ]);

my initial solution works but I want to use .map instead. So far I got 

let x = str.split(' ');
console.log(x.map(nums => nums.length))

but that won't return [] when passed through an empty array

Upvotes: 0

Views: 111

Answers (1)

Taki
Taki

Reputation: 17654

For the empty string, you'll get [ "" ] and the .map will return [ 0 ],

Filter out the 0 values : 

str.split(" ").map(nums => nums.length).filter(e => e);


const getWordLengths = str => {
  return str
    .split(" ")
    .map(nums => nums.length)
    .filter(e => e);
};

console.log(getWordLengths("")); //? []
console.log(getWordLengths("woooo")); //? [5]
console.log(getWordLengths("hello world")); //? [5, 5]
console.log(getWordLengths("like a bridge over troubled water")); //? [4, 1, 6, 4, 8, 5]

Upvotes: 2

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