CODEWITHSUNDEEP
python-3.x
Vicky
Vicky

Reputation: 35

How to rearrange a list of months in python in the form of calender year

I have a list in the form of:

months = ['August', 'September', 'October', 'November', 'December', 'January']

I need the output for the months to be arranged in the form of calendar year as below:

months : [January, 'August', 'September', 'October', 'November', 'December'].

I have been trying to define my custom sort function as shown below:

m = {"January":0, "February":1, "March":2, "April":3, "May":4, "June":5, "July":6, "August":7, "September":8, "October":9, "November":10, "December":11}

sorted(months,key=m)

But I am getting error as dict object is not callable.

I am not sure if this approach is right and how should I proceed in this case.

Upvotes: 0

Views: 110

Answers (2)

Ankit Agrawal
Ankit Agrawal

Reputation: 611

months = ['August', 'September', 'October', 'November', 'December', 'January']

order = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]

print(sorted(months,key=order.index))

Upvotes: 0

adnanmuttaleb
adnanmuttaleb

Reputation: 3624

key takes a function as value that is why you are getting the error. Try this:

sorted(months,key=lambda x: m[x])

Upvotes: 1

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