CODEWITHSUNDEEP
python-3.xmapboxgeoplotly-python
Viktor Avdulov
Viktor Avdulov

Reputation: 157

How to create a choropleth map using mapbox and plotly at a country level?

I am trying to create a choropleth map using plotly and mapbox similar to the US map https://plot.ly/python/mapbox-county-choropleth/ but of African countries. I am new to Python and coding period, so I am a bit lost. My geo data json doesn't have the 'id' field like the the Plotly example. Do I need to create one? Or do I need to just index by df by country? But then how do I match up the instances in the json file? Any help would be appreciated

with open('custom.geo.json') as response:
    africa_geo = json.load(response)
data=pd.read_csv('africa_project.csv')

data dataframe

africa_geo['features'][0]

{'type': 'Feature',
 'properties': {'scalerank': 0,
  'featurecla': 'Admin-0 country',
  'labelrank': 3,
  'sovereignt': 'Burkina Faso',
  'sov_a3': 'BFA',
  'adm0_dif': 0,
  'level': 2,
  'type': 'Sovereign country',
  'admin': 'Burkina Faso',
  'adm0_a3': 'BFA',
  'geou_dif': 0,
  'geounit': 'Burkina Faso',
  'gu_a3': 'BFA',
  'su_dif': 0,
  'subunit': 'Burkina Faso',
  'su_a3': 'BFA',
  'brk_diff': 0,
  'name': 'Burkina Faso',
  'name_long': 'Burkina Faso',
  'brk_a3': 'BFA',
  'brk_name': 'Burkina Faso',
  'brk_group': None,
  'abbrev': 'B.F.',
  'postal': 'BF',
  'formal_en': 'Burkina Faso',
  'formal_fr': None,
  'note_adm0': None,
  'note_brk': None,
  'name_sort': 'Burkina Faso',
  'name_alt': None,
  'mapcolor7': 2,
  'mapcolor8': 1,
  'mapcolor9': 5,
  'mapcolor13': 11,
  'pop_est': 15746232,
  'gdp_md_est': 17820,
  'pop_year': -99,
  'lastcensus': 2006,
  'gdp_year': -99,
  'economy': '7. Least developed region',
  'income_grp': '5. Low income',
  'wikipedia': -99,
  'fips_10_': 'UV',
  'iso_a2': 'BF',
  'iso_a3': 'BFA',
  'iso_n3': '854',
  'un_a3': '854',
  'wb_a2': 'BF',
  'wb_a3': 'BFA',
  'woe_id': 23424978,
  'woe_id_eh': 23424978,
  'woe_note': 'Exact WOE match as country',
  'adm0_a3_is': 'BFA',
  'adm0_a3_us': 'BFA',
  'adm0_a3_un': -99,
  'adm0_a3_wb': -99,
  'continent': 'Africa',
  'region_un': 'Africa',
  'subregion': 'Western Africa',
  'region_wb': 'Sub-Saharan Africa',
  'name_len': 12,
  'long_len': 12,
  'abbrev_len': 4,
  'tiny': -99,
  'homepart': 1,
  'filename': 'BFA.geojson'},
 'geometry': {'type': 'Polygon',
  'coordinates': [[[-0.3976712649999, 15.002134501000072],
    [-0.361471923999943, 15.017740784000113],
    [-0.29917598499992, 15.054741110000064],
    [-0.236699177999867, 15.065618999000035],
    [-0.166987670999902, 15.049676819000098],
    [-0.033404092999916, 14.995933329000096],
    [-0.033197387999962, 14.995933329000096],
    [0.218466838000012, 14.910977275000109],
    [0.22084395400006, 14.888213806000126],
    [0.211852254000121, 14.874803772000078],
    ...]]}}

fig = go.Figure(go.Choroplethmapbox(geojson=africa_geo, locations=data.country_name, z=data.ranking,
                                    colorscale="Viridis"))

fig.update_layout(mapbox_style="dark", mapbox_accesstoken=token,
                  mapbox_zoom=1, mapbox_center = {"lat": 6.6111, "lon": 20.9394})


fig.show()

enter image description here

Upvotes: 3

Views: 2989

Answers (2)

user2696565
user2696565

Reputation: 629

In go.Choroplethmapbox you can also point featureidkey to the property of geojson that you want to use as id. Say you have country name in your dataframe then you can simply set:

go.Choroplethmapbox(...,locations=df["country"],featureidkey="properties.admin", ...)

Upvotes: 2

Viktor Avdulov
Viktor Avdulov

Reputation: 157

Turns out that key is having the "id", a unique identifier called "id". If your geo.json doesn't have that it will not work. Then you have to associate the countries with the unique id and make sure your 'locations' is set equal to the df.id

enter image description here

Upvotes: 4

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