Reputation: 5
SELECT fee +
sum(((hourEnd-hourStart)*4) as sumAct3
from reserve join activity
on reserve.idactivity=activity.idactivity
join customer
on customer.idcustomer=reserve.idcustomer
where activity.typeAct=1 and customer.idcustomer='S1')
+
sum(((hourEnd-hourStart)*2) as sumAct2
from reserve join activity
on reserve.idactivity=activity.idactivity
join customer
on customer.idcustomer=reserve.idcustomer
where activity.typeAct=2 and customer.idcustomer='S1')
FROM customer
WHERE idcustomer='S1';
Ok, so every sum() returns the desired value, I already checked it but I'm having problems when trying to sum everything together and then get the total value.
Basically I have to do this:
But I don't know how I can make it work so I get a sum of everything, I tried for a while but I always get the "SELECT is not valid at this position"
Upvotes: 0
Views: 50
Reputation: 147266
You can get the sums of hours more readily by just JOIN
ing the tables to each other and using conditional aggregation to get the activity sums:
SELECT c.idcustomer,
SUM(CASE WHEN a.typeAct = 1 THEN hourEnd - hourStart ELSE 0 END) * 4 AS sumAct1,
SUM(CASE WHEN a.typeAct = 2 THEN hourEnd - hourStart ELSE 0 END) * 2 AS sumAct2
FROM customer c
JOIN reserve r ON r.idcustomer = c.idcustomer
JOIN activity a ON a.idactivity = r.idactivity
WHERE a.typeAct IN (1, 2) AND c.idcustomer = 'S1'
GROUP BY c.idcustomer
And then using this result as a derived table for the final addition:
SELECT c.idcustomer, c.fee + f.sumAct1 + f.sumAct2
FROM customer c
JOIN (
SELECT c.idcustomer,
SUM(CASE WHEN a.typeAct = 1 THEN hourEnd - hourStart ELSE 0 END) * 4 AS sumAct1,
SUM(CASE WHEN a.typeAct = 2 THEN hourEnd - hourStart ELSE 0 END) * 2 AS sumAct2
FROM customer c
JOIN reserve r ON r.idcustomer = c.idcustomer
JOIN activity a ON a.idactivity = r.idactivity
WHERE a.typeAct IN (1, 2) AND c.idcustomer = 'S1'
GROUP BY c.idcustomer
) f ON f.idcustomer = c.idcustomer
Upvotes: 2