CODEWITHSUNDEEP
ctimeformattingtimestamp
Nino
Nino

Reputation: 5401

strftime( ) doesn't display the seconds correctly

I tried strftime( ) to get a formatted time-stamp. 

char ft[ 256 ];
struct tm *tmp;
strftime( ft, 256, "%D - %T", tmp );

My problem is that I get "13/02/60 - 03:07:-17958194" as a result. Is there a way to display the seconds properly? (I'm using Mac OS X and gcc)

Upvotes: 0

Views: 1890

Answers (4)

Powerlord
Powerlord

Reputation: 88796

%s and %S are different formatting characters.

  • %s is the number of seconds since the unix epoch.
  • %S is the current time's seconds value (00-60) with a leading 0 for numbers < 10.

Upvotes: 1

Ryann Graham
Ryann Graham

Reputation: 8229

"%D - %T" should give you proper results, assuming you want "mm/dd/yy - hh:mm:ss".

If your example is accurate to your usage, you may want to consider giving the function a real time instead of some random address in memory.

Upvotes: 3

Douglas Leeder
Douglas Leeder

Reputation: 53310

You aren't initialising struct tm *tmp; with anything - please could you post a complete example?

Upvotes: 0

Michael Trausch
Michael Trausch

Reputation: 3165

You're using an uninitialized value in the code that you've posted, which would explain why you have this problem. The following code results in what you're looking for:

#include <stdio.h>
#include <time.h>

int
main(int argc, char *argv[]) {
  char ft[256];
  struct tm *tmp;
  time_t curtime;

  time(&curtime);
  tmp = localtime(&curtime);

  strftime(ft, 256, "%D - %T %s", tmp);
  printf("%s\n", ft);

  return(0);
}

Then, compile and run the example:

cc -o time_ex time_ex.c
./time_ex
02/26/09 - 11:26:34 1235665594

ETA: Drop the %s if you just want the local time without UNIX time after it, of course.

Upvotes: 7

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