Reputation: 1
I analyse data from being sent multiple ZIP files.
They are always in this format:
service_SC30COM_####_20191130_1834.zip
#### is a random number generated by the computer.
Password is SC30COM_####, which is always part of the file name.
Any suggestions on an automation to unzip in bulk?
Upvotes: 0
Views: 722
Reputation: 1090
There is no way to do it on the command prompt without any application. You can check this
If your remove the password, the code you need, as explain in that microsoft article should be:
$shell=new-object -com shell.application
$CurrentLocation=get-location
$CurrentPath=$CurrentLocation.path
$Location=$shell.namespace($CurrentPath)
$ZipFiles = get-childitem *.zip
$ZipFiles.count | out-default
foreach ($ZipFile in $ZipFiles)
{
$ZipFile.fullname | out-default
$ZipFolder = $shell.namespace($ZipFile.fullname)
$Location.Copyhere($ZipFolder.items())
}
If you install any application that can run on command prompt, you can extract with password. As example, for a individual file, the maximum you will get on Windows 10 is:
PowerShell Expand-Archive -Path "C:\Users\Tuffy\Desktop\PowerShell Expand-Archive -Path "C:\Users\Whatever\Desktop\service_SC30COM_####_20191130_1834.zip" -DestinationPath "C:\Users\Whatever\Desktop"p" -DestinationPath "C:\Whatever\Tuffy\Desktop"
Hope it helps!
Upvotes: 1
Reputation: 83
You can run the following code as a bash script:
#!/bin/bash
for FILE in *.zip
do
echo "Unzipping $FILE ..."
PASSWORD=$(echo $FILE | grep -o -P '(?<=service_)[A-Za-z0-9]*_[0-9]*(?=_)')
unzip -P $PASSWORD $FILE
done
Upvotes: 0