CODEWITHSUNDEEP
rust
Sumchans
Sumchans

Reputation: 3784

Having trouble accessing elements of a vector inside loop

I am trying to print the elements of a vector through the println! inside a loop.

This is the error I get, cant figure out what I am doing wrong. Please advise!

error[E0277]: the type `[i32]` cannot be indexed by `i32`
   |
21 |         s = v[outercount];
   |             ^^^^^^^^^^^^^ slice indices are of type `usize` or ranges of `usize`
   |
   = help: the trait `std::slice::SliceIndex<[i32]>` is not implemented for `i32`
   = note: required because of the requirements on the impl of `std::ops::Index<i32>` for `std::vec::Vec<i32>`

let v = vec![1,4,2,4,1,8];
let mut outercount:i32 = 0;
loop {
    outercount += 1;
    s = v[outercount];
    println!("{}", s);
    if outercount == (v.len() - 1) as i32 { break; }
}

Upvotes: 0

Views: 491

Answers (3)

Taimoor
Taimoor

Reputation: 81

I faced the similar problem few days ago but in a different manner when I was trying to make my bubble sort program in rust. I hope you got your answer as I can see. I think the way you wanted to print a vector is syntactically incorrect, here is an example of printing a vector in a loop. Hope this would help you.

fn main(){
let v = vec![1,3,5,7,9]; 
for i in v.iter(){ //also for i in &v 
  println!("{:?}",i);
 }
}

Also you can use 

let outercount = v[0]; //rust will automatically infer this as [i32]

Upvotes: 1

matiu
matiu

Reputation: 7725

I know this may not actually help your code @Sumchans, but I'm compelled to write a more idiomatic version. I hope that it helps someone:

fn main() {
   let v = vec![1,4,2,4,1,8];
   v.iter().for_each(|n| println!("{}", n));
}

Upvotes: 3

akuiper
akuiper

Reputation: 215117

As the error message suggests, index needs to be usize instead of i32:

let v = vec![1,4,2,4,1,8];
let mut outercount: usize = 0;    // declare outercount as usize instead of i32
loop {
    let s = v[outercount];        // need to declare variable here
    println!("{}", s);
    outercount += 1;
    if outercount == v.len() { break; }
}

Upvotes: 2

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