CODEWITHSUNDEEP
pythonpython-3.xdictionaryrounding
oceanicboy
oceanicboy

Reputation: 51

Round value in dictionary to nearest 5 in python?

I want to round to the nearest 5 an element in the value of a dictionary.

Given a dictionary:

d = {'0': '0 43 1000 27 3 I', '1': '2 52 1020 28 3 J', '2': '2 11 10 281 32 T'}

I want to return the second element in the value of each dict, and round it to the nearest 5. So round 43 to 45, 52 to 50 and 11 to 10.

So far I only know how to return the value of a key in the dict, 

for i in d['0']

but cant figure out the rest. Any help would be greatly appreciated.

Upvotes: 1

Views: 149

Answers (2)

Sarques
Sarques

Reputation: 463

If you don't want to use the round function in any case, the other way around by breaking the round function itself is this:

def doit(d):
    for key, value in d.items():
    nums = value.split(" ")
    if int(nums[1])%5>=3:
        print((int(nums[1])//5)*5+5)
    else:
        print((int(nums[1])//5)*5)

Thanks.

Upvotes: 0

chunpoon
chunpoon

Reputation: 970

To round to nearest 5, you can use a custom function:

def round_five(x):
    return 5 * round(x/5)

To access the second number in your string of numbers:

for k, v in d.items():
    # make a list out of the string
    nums = v.split(" ") 

    # round the 2nd element
    rounded = round_five(nums[1])

    # do something with the second element:
    print(rounded)

Upvotes: 3

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