Reputation: 175
Firstly, I know it would be more simple to achieve this using CSS but I am really trying to wrap my head around looping with JS as it is a new concept for me
What I want to happen is for the 'bg' class to loop through a number of background colours once
My code does not currently work would very much appreciate some direction :)
HTML
<div class="bg"></div>
CSS
.bg {
width: 100%;
height: 100%;
}
JS
var bg = document.getElementByClassName('bg');
var colours = ["#CCCDFF", "#BAC7E8", "#D9EEFF", "#BADFE8"];
for (i = 0; i < colours.length; i++) {
setInterval(change, 200);
function change() {
bg.style.background = colours;
}
}
Upvotes: 1
Views: 6233
Reputation: 650
const bg = document.querySelector('.bg');
const colours = ["#CCCDFF", "#BAC7E8", "#D9EEFF", "#BADFE8"];
(async () => {
for (const [index, colour] of colours.entries()) {
await new Promise(resolve => setTimeout(() => bg.style.background = colour, 200))
}
})()
await
keyword available. It awaits an asynchronous task. Upvotes: 1
Reputation: 25648
You missed an s
in getElementsByClassName
, and since it returns multiple DOM elements, you need to select the first one with [0]
, or, as suggested by @ScottMarcus, simply use querySelector
which will return the first element matching the selector you pass to it.
And when using setInterval
inside a loop with the same delay, they're all going to trigger at the same time. Here is another approach using setTimeout
:
var bg = document.querySelector('.bg');
var colours = ["#CCCDFF", "#BAC7E8", "#D9EEFF", "#BADFE8"];
chainColours(colours);
function chainColours(colours) {
if (colours.length) {
setColour(colours[0]);
setTimeout(function() {
chainColours(colours.slice(1)); // Repeat with all colours except the first one
}, 200);
}
}
function setColour(colour) {
bg.style.background = colour;
}
.bg {
width: 100px;
height: 100px;
}
<div class="bg"></div>
Here, we're using a recursive function (a function which calls itself).
The first time we call it, we pass it the entire array of colours. The if
condition will pass, because colours.length
will be truthy (different than 0
).
We set the bg colour to the first colour in that Array, using the setColour()
function.
And then, using setTimeout
, we wait 200ms to call the function again, but passing the Array without the first element, using slice
.
It will go on until there are no elements left in that passed Array. Then, the if
condition will not pass, and it will stop.
Upvotes: 1
Reputation: 65853
There are 3 big problems with this line:
var bg = document.getElementByClassName('bg');
getElementsByClassName()
. You missed an "s"..getElementsByClassName()
returns a node list (collection) of all matching
elements. The collection doesn't have a style
property, only
individual elements will. You'd have to extract an element from the
collection first and then access it's style
..getElementsByClassName()
returns a "live" node list, which hurts
performance quite a bit. It's a very old API and shouldn't be used
in 2019.Next, because the interval timer will run continuously at the specified interval, the loop is not required. The repeating nature of the timer acts as a loop.
Next, in your CSS, you specify your element's size using percents, but percents have to be relative to something else, otherwise they won't work. If you want the element to be as big as the page, use vw
and vh
(Viewport Width and Viewport Height).
// Don't use `.getElementsByClassName()`
var bg = document.querySelector('.bg');
var colours = ["#CCCDFF", "#BAC7E8", "#D9EEFF", "#BADFE8"];
var index = 0; // Will keep track of which color to use
function change() {
// If we have run out of colors, stop the timer
if(index >= colours.length){ clearInterval(timer); }
// Set the color and increment the index
bg.style.backgroundColor = colours[index++];
}
// Start the timer but get a reference to it
// so we can stop it later
var timer = setInterval(change, 200);
.bg {
width: 100vw;
height: 100vh;
}
<div class="bg"></div>
Upvotes: 5
Reputation: 1908
setInterval
will schedule a function to be called after a certain interval. It is non-blocking, so execution will proceed immediately after the function is queued. In this case, you're scheduling all four color changes to happen after 200 milliseconds, so the callbacks will be fired simultaneously.
Instead, you could do something like this: setInterval(change, 200 * i)
Upvotes: 0