Reputation: 165
I try to merge two arrays of objects and at the same time add their name as a property to the objects:
const firstGroup = [
{
firstname: 'Nick',
id: 1
},
{
firstname: 'Joe',
id: 2
},
]
const secondGroup = [
{
firstname: 'Tom',
id: 1
},
]
The desired output:
allGroups = [
{
groupname: 'firstGroup',
firstname: 'Nick',
id: 1
},
{
groupname: 'firstGroup',
firstname: 'Joe',
id: 2
},
{
groupname: 'secondGroup',
firstname: 'Tom',
id: 1
}
]
Here is what I tried:
Object
.entries({ firstGroup, secondGroup })
.reduce((acc, [name, [firstname, id]]) => ([{
...acc,
groupname: name,
firstname,
id
}]), [])
But it doesn't work and I can't figure out how I can do it.
Thanks for your help !
Upvotes: 3
Views: 242
Reputation: 1075337
Your code was close, but you're creating a new array on each iteration rather than modifying the "accumulator" array reduce
passes around, and only taking the properties from the first entry in the source array, not all of them.
reduce
just adds complexity here IMHO, I'd use a for-of
loop over the entries of the object you created. Within the loop body, map the entries to new entries with the group name, then push them all on allGroups
. Like this:
const allGroups = [];
for (const [groupname, entries] of Object.entries({firstGroup, secondGroup})) {
allGroups.push(...entries.map(entry => ({groupname, ...entry})));
}
Live Example:
const firstGroup = [
{
firstname: 'Nick',
id: 1
},
{
firstname: 'Joe',
id: 2
},
];
const secondGroup = [
{
firstname: 'Tom',
id: 1
},
];
const allGroups = [];
for (const [groupname, entries] of Object.entries({firstGroup, secondGroup})) {
allGroups.push(...entries.map(entry => ({groupname, ...entry})));
}
console.log(allGroups);
But here's a working version of your reduce
approach:
const firstGroup = [
{
firstname: 'Nick',
id: 1
},
{
firstname: 'Joe',
id: 2
},
];
const secondGroup = [
{
firstname: 'Tom',
id: 1
},
];
const allGroups = Object.entries({ firstGroup, secondGroup })
.reduce((acc, [groupname, entries]) => {
acc.push(...entries.map(entry => ({groupname, ...entry})));
return acc;
}, []);
console.log(allGroups);
In a comment you've asked:
...what if I want in the final object just a selection of the initial properties eg.
groupname
,firstname
but notid
?
You'd change the places above where I have entry =>
to ({firstname}) =>
to destructure the listed property(ies) from the object, and change where I have ...entry
to firstname
to fill in just that/those properties on the new object. So for instance:
allGroups.push(...entries.map(({firstname}) => ({groupname, firstname})));
Live example - for-of
:
const firstGroup = [
{
firstname: 'Nick',
id: 1
},
{
firstname: 'Joe',
id: 2
},
];
const secondGroup = [
{
firstname: 'Tom',
id: 1
},
];
const allGroups = [];
for (const [groupname, entries] of Object.entries({firstGroup, secondGroup})) {
allGroups.push(...entries.map(({firstname}) => ({groupname, firstname})));
}
console.log(allGroups);
Live example - reduce
:
const firstGroup = [
{
firstname: 'Nick',
id: 1
},
{
firstname: 'Joe',
id: 2
},
];
const secondGroup = [
{
firstname: 'Tom',
id: 1
},
];
const allGroups = Object.entries({ firstGroup, secondGroup })
.reduce((acc, [groupname, entries]) => {
acc.push(...entries.map(({firstname}) => ({groupname, firstname})));
return acc;
}, []);
console.log(allGroups);
Upvotes: 4
Reputation: 57214
If you have access to it, you can use flatMap
or flat
to avoid using reduce
entirely.
Passing an array to reduce
and pushing an item onto the accumulator per element is an antipattern because map
does this specific operation (applying a callback to every item in an array) with cleaner syntax and semantics. The only reason reduce
was chosen is because a flattening operation is needed, but flatMap
expresses this intent more clearly.
const firstGroup = [{firstname: 'Nick', id: 1}, {firstname: 'Joe', id: 2}];
const secondGroup = [{firstname: 'Tom', id: 1}];
const result = Object.entries({firstGroup, secondGroup})
.flatMap(([groupname, arr]) => arr.map(({id, firstname}) => ({
groupname, firstname, id
})))
;
console.log(result)
Using flat
:
const firstGroup = [{firstname: 'Nick', id: 1}, {firstname: 'Joe', id: 2}];
const secondGroup = [{firstname: 'Tom', id: 1}];
const result = Object.entries({firstGroup, secondGroup})
.map(([groupname, arr]) => arr.map(({id, firstname}) => ({
groupname, firstname, id
})))
.flat()
;
console.log(result)
If you don't have access to either, there's spread/concat
:
const firstGroup = [{firstname: 'Nick', id: 1}, {firstname: 'Joe', id: 2}];
const secondGroup = [{firstname: 'Tom', id: 1}];
const result = [].concat(...Object.entries({firstGroup, secondGroup})
.map(([groupname, arr]) => arr.map(({id, firstname}) => ({
groupname, firstname, id
}))))
;
console.log(result)
Upvotes: 1
Reputation: 464
Below snippet of code can be used to achieve the result.
Object.entries({ firstGroup, secondGroup }).reduce((acc, [groupname, groupItems]) => {
for (item of groupItems){
acc.push({
...item,
groupname
});
}
return acc;
}, [])
Upvotes: 1
Reputation: 789
No need to over complicate things, this will work just fine:
const firstGroup = [
{
firstname: 'Nick',
id: 1
},
{
firstname: 'Joe',
id: 2
},
]
const secondGroup = [
{
firstname: 'Tom',
id: 1
},
]
firstGroup.map(x => x.groupname = 'firstGroup');
secondGroup.map(x => x.groupname = 'secondGroup');
const allGroups = [].concat(firstGroup, secondGroup);
console.log(allGroups);
Upvotes: -1