CODEWITHSUNDEEP
python
Ross1103
Ross1103

Reputation: 1

Print line number of text file

Very new to python and self teaching at the moment, so apologies if the example is wrong/basic. Feel free to improve it :)

Basically the file MEs.txt contains a list of IP addresses, once it pings the ip address and gets a response I was trying to get the printout of 'ME (line number) is connected/disconnected).

Any help?


os.remove("EquipmentCheck.txt")

file = open("MEs.txt", "r+")

with open("MEs.txt", "r") as file:

  for line in file:
     response = os.system("ping   " + line)

     if response == 0:
        with open("EquipmentCheck.txt", "a") as file:
                file.write("ME is connected" "\n")

     else:
         with open("EquipmentCheck.txt", "a") as file:
                file.write("ME is disconnected" "\n")```

Upvotes: 0

Views: 123

Answers (3)

veryyynice
veryyynice

Reputation: 1

You have 2 variables named file, they're breaking the code

Upvotes: 0

Guilherme
Guilherme

Reputation: 1835

try with enumerate()

enumerate(iterable, start=0)

Parameters:

Iterable: any object that supports iteration
Start: the index value from which the counter is to be started, by default it is 0

with open("MEs.txt") as fp:
    for i, line in enumerate(fp):
        print("%d, %s"%(i, line))

Upvotes: 0

schillingt
schillingt

Reputation: 13731

One option is to use the enumerate function.

  for index, line in enumerate(file):
     line_number = index + 1
     ...

Apparently there's a start parameter. So you could do:

  for line_number, line in enumerate(file, start=1):
     ...

Upvotes: 4

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