Reputation: 33
from datetime import datetime
with open('directory.csv','r') as file:
r=csv.reader(file)
for i in r:
if i[0]!=' NAME ':
data = sorted(r, key = lambda row: datetime.strptime(row[1], "%y/%m/%d"))
print(data)
the above is my code.
and this is the output that comes:
ValueError: time data '2002/3/13' does not match format '%y/%m/%d'
Upvotes: 2
Views: 42
Reputation: 117856
The Y
needs to be capitalized
>>> datetime.strptime('2002/3/13', '%Y/%m/%d')
datetime.datetime(2002, 3, 13, 0, 0)
From the docs
%y
Year without century as a zero-padded decimal number. (00, 01, ..., 99)
%Y
Year with century as a decimal number (0001, 0002, …, 2013, 2014, …, 9998, 9999)
Upvotes: 3