CODEWITHSUNDEEP
shellfileunixsearch
Prasad Jayathilake
Prasad Jayathilake

Reputation: 29

Search Unix file name by positions of the characters in file name

I have 2 files.

`File 1 = ABC2019120601C`
`File 2 = ABC2019120611C`

If I type ls -l ABC*C it will output all 2 files. Is there a way to find files by exact position of the character?

For example
1st position = A
2nd position = B
3rd position = C
and 14th position = C

Then it will output only the file ABC2019120601C

Please help if this is possible

Thanks

Upvotes: 0

Views: 322

Answers (2)

dash-o
dash-o

Reputation: 14442

On surface, the ASK is to find files regardless of the embedded date-time (probably YYYYMMDDHH). This translates into 'ABC[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]C' pattern. Either printf or find will work.

# Single Folder
printf '%s\n' ABC[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]C

# Multiple folders, deep search
find /folder1 /folder2 -name 'ABC[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]C'

Upvotes: 0

root
root

Reputation: 6048

Bash globbing has more than just *, e.g. ?, which means "any single character":

$ ls -1 ABC*C
ABC2019120601C
ABC2019120611C
$ ls -1 ABC????????0??
ABC2019120601C
$ ls -1 ABC????????1??
ABC2019120611C

Upvotes: 1

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