CODEWITHSUNDEEP
pythonpython-3.xsockets
bas.cmd
bas.cmd

Reputation: 45

Python socket outputing wrong arguments

I am trying to get my python code to work on python 3. In python 2 it worked properly but when i put it in python 3 it recieves the wrong text from the socket. In python 2 it recieved stop but in python 3 it recieves b'stop'. And i can't find out why.

Mycode:

import socket
import sys
import subprocess

HOST = '192.168.176.71'
PORT = 8888

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

print('socket created')

try:
    s.bind((HOST, PORT))
except socket.error as err:
    print('Bind Failed, Error Code: ' + str(err[0]) + ', Message: ' + err[1])
    sys.exit()

print('Socket Bind Success!')


s.listen(10)
print('Socket is now listening')


while 1:
    conn, addr = s.accept()
    print('Connect with ' + addr[0] + ':' + str(addr[1]))
    buf = conn.recv(4096)
    if buf == "stop":
        print("stoping")
        exit()
    print(buf)
s.close()

Upvotes: 0

Views: 48

Answers (1)

Chris Doyle
Chris Doyle

Reputation: 12027

'stop' is a string and b'stop' is a bytes object not a string.

The documentation of python 3 for recv() says:

Receive data from the socket. The return value is a bytes object representing the data received.

The documentation for python 2 recv() says:

The return value is a string representing the data received.

So the behaviour is correct in python 2 you receive a string but in python 3 you receive bytes. So if you want this as a string then you need to decode it.

data = bytes('stop'.encode())
print(data)
print(data.decode())
print(data == 'stop')
print(data.decode() == 'stop')

OUTPUT

b'stop'
stop
False
True

Upvotes: 1

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