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c++lambdastdpriority-queue
Edamame
Edamame

Reputation: 25366

c++: priority_queue: lambda-expression in template-argument

I am trying to create a priority_queue with each element as a 3D vector. The element whose third dimension has the largest value would become the priority element.

Here is my code:

   priority_queue< vector<int>, vector<vector<int>>, [](vector<int> &v1, vector<int> &v2){
        return v1[2] > v2[2];
    }> pq{};

but I got the following error:

error: lambda-expression in template-argument

Any idea what I did wrong? Thanks!

Upvotes: 2

Views: 198

Answers (1)

n314159
n314159

Reputation: 5075

You cant have a lambda (which is an object) in a type template declaration (where a type is needed. Do instead:

auto lambda =  [](vector<int> &v1, vector<int> &v2){
    return v1[2] > v2[2];
};
priority_queue< vector<int>, vector<vector<int>>,decltype(lambda)> pq{lambda};

We also need to pass the lambda since it is not default constructible.

Form C++20 on, we can do the following:

priority_queue< vector<int>, vector<vector<int>>,decltype([](vector<int> &v1, vector<int> &v2){
    return v1[2] > v2[2];
};
)> pq{};

Here there come two new featurs of lambdas into play. First that you can take the type of it directly (formally: In C++17 you cannot have a lambda-expression in unevaluated context) and second that lambdas are default constructible. But right now, that is not yet possible.

Upvotes: 4

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