CODEWITHSUNDEEP
regexsedgnuwin32
Yurii Kosiak
Yurii Kosiak

Reputation: 410

Remove duplicate words in a line with sed GnuWin32

I'm trying to remove repeated words in a text. The same issue described at these articles: Remove duplicate words in a line with sed and there: Removing duplicate strings with SED But these variants not work for me. May be becouse I'm using GnuWin32

Example what result I need:

Input

One two three bird animal two bird

Output

One two three bird animal

Upvotes: 0

Views: 310

Answers (4)

FGrose
FGrose

Reputation: 51

For unique words that may include -- - / ' etc (where \< & \> would break the 'word', such as an option in a kernel command line):

  1. Pad the input string with a space before and after, " $string " below
  2. string=$(sed -E ':a;s/(\s(\S+)\s.*)\2\s/\1/;ta' <<< " $string ")
  3. Remove the pads, string=${string# }; string=${string% }

Upvotes: 0

kvantour
kvantour

Reputation: 26481

The tool sed is not really designed for this work. sed only has two forms of memory, the pattern-space and the hold-space, which are nothing more then two simple strings it can remember. Every time you do an operation on such memory-block, you have to rewrite the full memory block and reanalyze it. Awk, on the other hand, has a bit more flexibility in here and makes it easier to manipulate the lines in question.

awk '{delete s}
     {for(i=1;i<=NF;++i) if(!(s[$i]++)) printf (i==1?"":OFS)"%s",$i}
     {printf ORS}' file

But since you work on windows machine, it also means you have CRLF line-endings. This might create slight problems with the last entry. If the line reads:

foo bar foo

awk would read it as

foo bar foo\r

and thus the last foo will not match the first foo due to the CR.

A correction would now read:

awk 'BEGIN{RS=ORS="\r\n"}
     {delete s}
     {for(i=1;i<=NF;++i) if(!(s[$i]++)) printf (i==1?"":OFS)"%s",$i}
     {printf ORS}' file

This can be used since you use CygWin which is in the end GNU, so we can use the extension on of RS to be a regex or multi-character value.

If you want case-sensitivity you can replace s[$i] with s[tolower($i)].

There are still issues with sentences like

"There was a horse in the bar, it ran out of the bar."

The word bar could be matched here, but the , and . make it not match. This can be solved with:

awk 'BEGIN{RS=ORS="\r\n"; ere="[,.?:;\042\047]"}
     {delete s}
     {for(i=1;i<=NF;++i) {
        key=tolower($i); sub("^" ere,"",key); sub(ere "$","",key)
        if(!(s[key]++)) printf (i==1?"":OFS)"%s",$i
      } 
     }
     {printf ORS}' file

This essentially does the same, but removes the punctuation marks at the beginning and end of a word. The punctuation marks are listed in ere

Upvotes: 2

Adam Katz
Adam Katz

Reputation: 16138

I think this would be far faster in awk.

This should work on any platform, but I have not verified it on Windows:

awk '{
  sp = "";
  delete seen;
  for (i=1; i<=NF; i++) if (!seen[$i]++) { printf "%s%s", sp, $i; sp = " "; }
  printf "\n";
}' file

(Feel free to condense that onto one line, it'll work fine.)

AWK is great at columnar data. By default, it divides each line's text into fields separated by contiguous white space (so given hello world, we get $1 = "hello" and $2 = "world"). The special NF variable is the number of fields it found, so for (i=1; i<=NF; i++) iterates over each field (word) as i whose value is $i.

I'm using an associative array here (aka a dictionary or hash). The seen array at index $i (the current word) starts as zero (uninitialized). We increment it, but just like C, awk uses x++ to increment x but return its original value (contrast to ++x which increments and returns the incremented value). Therefore, !seen[$i]++ is true (!0) when we haven't yet incremented the array at this word—it is new to us. seen is cleared at each line so we have unique words per line rather than across the whole file.

Knowing that we haven't seen it, we need to print it. Note, the original white space between words is lost (it's not stored anywhere). We just print a space (but not at the beginning of a new line, thus the sp variable) and then the new word.

After the for loop, we complete the line. There will never by any trailing spaces. (Also, the actual line ending is lost, so we're assuming it's \n. If you want DOS line endings, use \r\n.)

Upvotes: 3

potong
potong

Reputation: 58430

This might work for you (GNU sed):

sed -E ':a;s/\<((\S+)\>.*)\s\<\2\>/\1/gi;ta' file

Match any word and remove the preceeding white space and its duplicate. Repeat.

N.B. The regexp removes duplicates without regard to case. If you want to treat One separately to one use:

sed -E ':a;s/\<((\S+)\>.*)\s\<\2\>/\1/g;ta' file

Upvotes: 1

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