CODEWITHSUNDEEP
python-3.x
IYSZ
IYSZ

Reputation: 27

how to check with boolean if input is integer even casting input as integer

I am failing at an optional task where i check the input of int(input("my string")) with .isdigit()

without this optional task i solved task but i want to learn efficient so i need your help guys.

The task

get input of 2 integer numbers cast the input and print the input followed by the result Output Example: 9 + 13 = 22

Optional: check if input .isdigit() before trying integer addition to avoid errors in casting invalid inputs

My code so far

int_nmbr1 = int(input("Enter first number: "))
int_nmbr2 = int(input("Enter second number: "))
if int_nmbr1.isdigit() & int_nmbr2.isdigit() == True: #Here i check it with is.digit() twice
print(int_nmbr1, " + ", int_nmbr2, " = ", int_nmbr1 + int_nmbr2)

Console Error Output

AttributeError Traceback (most recent call last) in () 3 int_nmbr2 = int(input("Enter second number: ")) 4 ----> 5 if int_nmbr1.isdigit() & int_nmbr2.isdigit() == True: 6 print(int_nmbr1, " + ", int_nmbr2, " = ", int_nmbr1 + int_nmbr2)

AttributeError: 'int' object has no attribute 'isdigit'

Upvotes: 0

Views: 772

Answers (1)

theashwanisingla
theashwanisingla

Reputation: 477

You’re trying to implement isdigit on int data type while it is a method of str. By using int(input()), your input is already an int value if you enter any value with base10. So you don’t need to use isdigit. isdigit is used to check if it is any digit in string format. If you’ve still any doubt, you can check dir(str) and dir(int). And furthermore, you can check the print(help(str.isdigit)).

And now, in case of wrong data type entered, you can use exception handelings. You can use it like this:

try:
    int(input(“enter any number:”))
except ValueError:
    print(“Please enter any integer value only”)
    int(input(“enter any number:”))

Above code will not return error if you’ll enter any other data type instead of integer for first time.

Upvotes: 0

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