CODEWITHSUNDEEP
python-3.xkivy
utkarshver
utkarshver

Reputation: 87

Access attributes of a different screen

How do I access img_path and img attributes of class(screen) E1 inside Guide? I'm doing it currently as shown in the code below, but it throws an error saying AttributeError: 'super' object has no attribute '__getattr__'.

I read a number of answers on this and figured that I have to declare these as StringProperty() maybe, but they all had a separate .kv file where they defined the screens so I couldn't figure out how to do the same with my piece of code. 

class E1(GridLayout):
    ...
    ...
    self.img_path = "./Images/e1.jpg"
    self.img = Image(source = self.img_path)
    ...
    ...

class GuideOP(GridLayout):
    ...
    ...
    self.img_path = app.screen_manager.get_screen("E1").ids.img_path.get()
    self.img = app.screen_manager.get_screen("E1").ids.img.get()
    ...
    ...

class MyApp(App):
    def build(self):
        self.screen_manager = ScreenManager()

        self.e1_page = E1()
        screen = Screen(name = "E1")
        screen.add_widget(self.e1_page)
        self.screen_manager.add_widget(screen)

        self.guide_page = GuideOP()
        screen = Screen(name = "GuideOP")
        screen.add_widget(self.guide_page)
        self.screen_manager.add_widget(screen)

        return self.screen_manager

Upvotes: 0

Views: 35

Answers (1)

John Anderson
John Anderson

Reputation: 38837

If you are not using a kv file, then you cannot use ids. That is likely the source of the error message.

Assuming that 

self.guide_page = GuideOP()

is actually meant to use the

class Guide(GridLayout)

Then, I think you can try: 

self.img_path = app.screen_manager.get_screen("E1").children[0].img_path
self.img = app.screen_manager.get_screen("E1").children[0].img

I haven't tested this code, but I think it should work. Note that the E1 Widget is a child of the Screen named E1. Thus the use of children[0]. This assumes that there are no other children of that Screen.

Upvotes: 1

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