Reputation: 107
I am not sure if I am asking this correctly and maybe that is the reason why I didn't find the correct answer so far. Anyway, if it will be duplicate I will delete this question.
I have following data:
id | last_updated | count
__________________________
1 | 20190101 | 3
1 | 20190201 | 2
1 | 20190301 | 1
I want to group by this data by "id" column, get max value from "last_updated" and regarding "count" column I want keep value from row where "last_updated" has max value. So in that case result should be like that:
id | last_updated | count
__________________________
1 | 20190301 | 1
So I imagine it will look like that:
df
.groupBy("id")
.agg(max("last_updated"), ... ("count"))
Is there any function I can use to get "count" based on "last_updated" column.
I am using spark 2.4.0.
Thanks for any help
Upvotes: 3
Views: 2521
Reputation: 7928
You have two options, the first the better as for my understanding
OPTION 1 Perform a window function over the ID, create a column with the max value over that window function. Then select where the desired column equals the max value and finally drop the column and rename the max column as desired
val w = Window.partitionBy("id")
df.withColumn("max", max("last_updated").over(w))
.where("max = last_updated")
.drop("last_updated")
.withColumnRenamed("max", "last_updated")
OPTION 2
You can perform a join with the original dataframe after grouping
df.groupBy("id")
.agg(max("last_updated").as("last_updated"))
.join(df, Seq("id", "last_updated"))
QUICK EXAMPLE
INPUT
df.show
+---+------------+-----+
| id|last_updated|count|
+---+------------+-----+
| 1| 20190101| 3|
| 1| 20190201| 2|
| 1| 20190301| 1|
+---+------------+-----+
OUTPUT Option 1
import org.apache.spark.sql.expressions.Window
import org.apache.spark.sql.functions
val w = Window.partitionBy("id")
df.withColumn("max", max("last_updated").over(w))
.where("max = last_updated")
.drop("last_updated")
.withColumnRenamed("max", "last_updated")
+---+-----+------------+
| id|count|last_updated|
+---+-----+------------+
| 1| 1| 20190301|
+---+-----+------------+
Option 2
df.groupBy("id")
.agg(max("last_updated").as("last_updated")
.join(df, Seq("id", "last_updated")).show
+---+-----------------+----------+
| id| last_updated| count |
+---+-----------------+----------+
| 1| 20190301| 1|
+---+-----------------+----------+
Upvotes: 2