CODEWITHSUNDEEP
scalasequenceimmutabilitymutable
reyman64
reyman64

Reputation: 553

How to convert immutable Seq to mutable seq with until loop

I'm trying to return a mutable Sequence with an until loop, but i have an immutable seq in return of (0 until nbGenomes) : 

 def generateRandomGenome(nbGenomes:Int): IndexedSeq[GenomeDouble]={
    return ((0 until nbGenomes toSeq).map{e => generateRandomGenome}) 
  }

Return compilation error :

found   : scala.collection.immutable.IndexedSeq[org.openmole.tools.mgo.mappedgenome.genomedouble.GenomeDouble]
 required: scala.collection.mutable.IndexedSeq[org.openmole.tools.mgo.mappedgenome.genomedouble.GenomeDouble]
    return ((0 until nbGenomes toSeq).map{e => generateRandomGenome})

How i can force the until loop to return an mutable seq ? Thanks scala community!

Upvotes: 11

Views: 9056

Answers (2)

Kim Stebel
Kim Stebel

Reputation: 42037

You can convert an immutable sequence to a mutable one by creating a new mutable sequence with the varargs constructor.

scala> val l = List(1,2,3)
l: List[Int] = List(1, 2, 3)
scala> scala.collection.mutable.ArraySeq(l:_*)
res0: scala.collection.mutable.ArraySeq[Int] = ArraySeq(1, 2, 3)

Upvotes: 12

David Winslow
David Winslow

Reputation: 8590

If the compiler knows which collection type to expect (and it does here as indicated by the error message) you can use scala.collection.breakOut to allow the type to be inferred based on the expected type for the expression rather than the type of the collection itself.

def generateRandomGenomes(n: Int): collection.mutable.IndexedSeq[Double] =
  (0 until n).map(_ => util.Random.nextDouble())(collection.breakOut)

(I tweaked your example a bit to stick to well-known types.)

Most (all?) collection types have some handy factory methods on their companion objects. So another way of accomplishing the same thing is to use scala.collection.mutable.IndexedSeq.fill:

def generateRandomGenomes(n: Int): collection.mutable.IndexedSeq[Double] =
  collection.mutable.IndexedSeq.fill(n)(util.Random.nextDouble())

Upvotes: 3

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