CODEWITHSUNDEEP
pythonpython-3.x
liorblob
liorblob

Reputation: 537

Prototyping base classes

I have a strange case where I have to inherit from a class that is defined later in my python file, like the following:

class Client(BaseClient):
    def __init__(self, url):
       super().__init__(url)
    ...

...

class BaseClient:
    def __init__(self, url):
    ...

I cannot do that because BaseClient is not defined when I inherit from it. Is there a way to prototype the base class in the beginning of my code so it works? Or maybe another workaround?

Upvotes: 0

Views: 108

Answers (2)

liorblob
liorblob

Reputation: 537

Perhaps I can give up the inheritance and pull something like this:

class Client:
    def __init__(self, base_client):
       self.base_client = base_client
    ...

def main()
    base_client = BaseClient(url)
    client = Client(base_client)
    client.base_client.do_stuff()
    client.do_other_stuff()

class BaseClient:
    def __init__(self, url):
    ...

main()

Upvotes: 0

Andrej Kesely
Andrej Kesely

Reputation: 195438

One solution is to define it inside a function:

def get_class():
    class Client(BaseClient):
        def __init__(self, url):
           super().__init__(url)

    return Client

class BaseClient:
    def __init__(self, url):
        self.url = url

Client = get_class()

c = Client('hello')
print(c.url)

Prints:

hello

Note: Do this only if there isn't any other (more clean) solution. The code could get ugly very fast...

Upvotes: 2

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