CODEWITHSUNDEEP
c++arraysmultidimensional-array
M.M.
M.M.

Reputation: 77

How do I take transpose of a 2D array without declaring another array?

array:

1 2 3
4 5 6

The output I want:

1 4
2 5
3 6

My code:

for (i = 0; i < rows; i++) {
  for (j = 0; j < col; j++) {
    temp = matrix[j][i];
    matrix[j][i] = matrix[i][j];
    matrix[i][j] = temp;
  }
}

for (i = 0; i < col; i++) {
  for (j = 0; j < rows; j++) {
    cout << setw(5) << matrix[i][j];
  }
  cout << endl;
}

where number of rows and columns, and the elements of array were taken from the user.

The output I am getting:

1 2
4 5
3 6

Any and every help will be appreciated.

Upvotes: 0

Views: 486

Answers (1)

ignacio
ignacio

Reputation: 1197

Try making for (j = i; j < col; j++) instead of for (j = 0; j < col; j++) in your matrix loop, because you should not go back to values that were already changed.

Upvotes: 1

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