CODEWITHSUNDEEP
python
V Levasseur
V Levasseur

Reputation: 9

I need to do an n x n block in Python to display "*" for that block

size = int(input("please enter an integer:"))
for row in range(size*1):
    print("*", end="")
print()
for column in range(1* size):
    print("*", end="")
print()

This is my code so far and I need it to print: for 2 

**
**

and for 7

*******
*******
*******
*******
*******
*******
*******

I have gotten it to print

**
**

for 2 but for 7 I just get

*******
*******

Upvotes: 0

Views: 90

Answers (4)

Zydnar
Zydnar

Reputation: 1502

Another way is to simply multiply strings - no loops:


size = int(input("please enter an integer:"))
print((('*'*size)+'\n')*size)

enjoy :D :D :D

Upvotes: 0

kaya3
kaya3

Reputation: 51044

The natural way to write this in many languages would use a nested loop. However, it is much easier in Python:

for i in range(size):
    print('*' * size)

Upvotes: 1

Guillaume Jacquenot
Guillaume Jacquenot

Reputation: 11717

You need to nest the two loops to achieve what you desire.

You can do it the following three lines with two tricks:

  • You can generate a string of n '*' with the command "*" * size, therefore you need a single loop
  • The for loop does not need an index, that is not used, so you can use _

The code looks like this:

size = int(input("please enter an integer:"))
for _ in range(size):
    print("*" * size)

Upvotes: 0

Haytam
Haytam

Reputation: 4733

You need to nest the for loops since you want the number of lines to be equal to the number of columns:

size = int(input("please enter an integer:"))
for row in range(size):
    for col in range(size):
        print('*', end="")
    print()

PS: You don't really have to mulitply by 1 in range.

Upvotes: 0

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