CODEWITHSUNDEEP
c++polymorphismvirtual-functions
crazypicklerick
crazypicklerick

Reputation: 39

Can I call a virtual function that is overridden from main()?

I know this


// C++ program for function overriding 

#include <bits/stdc++.h> 
using namespace std; 

class base 
{ 
public: 
    virtual void print () 
    { cout<< "print base class" <<endl; } 

    void show () 
    { cout<< "show base class" <<endl; } 
}; 

class derived:public base 
{ 
public: 
    void print () //print () is already virtual function in derived class, we could also declared as virtual void print () explicitly 
    { cout<< "print derived class" <<endl; } 

    void show () 
    { cout<< "show derived class" <<endl; } 
}; 

//main function 
int main()  
{ 
    base *bptr; 
    derived d; 
    bptr = &d; 

    //virtual function, binded at runtime (Runtime polymorphism) 
    bptr->print();  

    // Non-virtual function, binded at compile time 
    bptr->show();  

    return 0; 
}

I can get printed

print derived class
show base class
show derived class

can I print

print base class

with the object d of the derived class with just changing main() and without creating another object? if yes how?

Upvotes: 2

Views: 147

Answers (1)

R Sahu
R Sahu

Reputation: 206737

can I print print base class with the object d of the derived class with just changing main()

Yes, you can. You have to explicitly use the base class in the call.

bptr->base::print();

You can also use d directly.

d.base::print();

Upvotes: 11

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