CODEWITHSUNDEEP
pythonpython-3.xtic-tac-toe
elch
elch

Reputation: 11

How do you keep one letter a color and the rest another color?

tl;dr output all is in blue for tic tac toe, only want x as blue and o as red

In class we're trying to make a tic tac toe game and currently we're trying to modify the code in such a way that only X is blue and O is red however when we import colorama it colors all of the output. I am aware that all of the text will print in blue. So essentially it should look like: enter image description here I've also provided the code for the game.

import random
import colorama 
from colorama import Fore, Style
print(Fore.BLUE + "Hello World")
player_1_pick = ""
player_2_pick = ""

if (player_1_pick == "" or player_2_pick == ""):
  if (player_1_pick == ""):
    player_1_pick = "Player 1"
  if (player_2_pick == ""):
    player_2_pick = "Player 2"
else:
  pass

board = ["_"] * 9

def print_board():
  print(board[0] + '|' + board[1] + '|' + board[2])
  print(board[3] + '|' + board[4] + '|' + board[5])
  print(board[6] + '|' + board[7] + '|' + board[8])

print_board()
if (random.randint(1,2) == 1):
  player_1_pick = input(player_1_pick + ", choose X or O: ").upper()
  if (player_1_pick == "X"):
    player_2_pick = "O"



while True:
  x = input('Pick a number from 0-8')
  x = int(x)
  board[x] = 'X'
  print_board()

Then we decided to open another tab of python (we're using repl.it) to try and fix the problem in an isolated environment, in which we came up with:

import random
import colorama 
from colorama import Fore, Style
def getPieceLabel(piece):
  if (piece == 1):
    return "|" + color.PURPLE + color.BOLD + "X" + color.END + "|"
  elif (piece == 2 ):
    return "|" + color.BLUE + color.BOLD + "O"
    + "|" 
  else:
    return color.BOLD + "|_|" + color.END 

board = ["_"] * 9

def print_board():
  print(board[0] + '|' + board[1] + '|' + board[2])
  print(board[3] + '|' + board[4] + '|' + board[5])
  print(board[6] + '|' + board[7] + '|' + board[8])
  print(Style.RESET_ALL)

while True:
  x = input('Pick a number from 0-8')
  x = int(x)
  board[x] = 'X'
  print_board()

We need some help figuring this out/what the problem is.

Upvotes: 0

Views: 357

Answers (1)

IamAshKS
IamAshKS

Reputation: 823

Here is a code that works for printing different color for different items (tested on repl.it too!).

import random
import colorama 
from colorama import Fore, Style

print(Fore.BLUE + "Tic Tac Toe")
Style.RESET_ALL

player_1_pick = ""
player_2_pick = ""

if (player_1_pick == "" or player_2_pick == ""):
  if (player_1_pick == ""):
    player_1_pick = "Player 1"
  if (player_2_pick == ""):
    player_2_pick = "Player 2"
else:
  pass

board = ["_"] * 9

def print_board():
  for i in range(0, 3):
    for j in range(0, 3):
      if (board[i*3 + j] == 'X'):
        print(Fore.BLUE + board[i*3 + j], end = '')
      elif (board[i*3 + j] == 'O'):
        print(Fore.RED + board[i*3 + j], end = '')
      else:
        print(board[i*3 + j], end = '')

      print(Style.RESET_ALL, end = '')

      if j != 2:
        print('|', end = '')

    print() # new line

print_board()

if (random.randint(1,2) == 1):
  player_1_pick = input(player_1_pick + ", choose X or O: ").upper()
  if (player_1_pick == "X"):
    player_2_pick = "O"

while True:
  x = input('Pick a number from 0-8: ')
  x = int(x)
  board[x] = 'X'
  print_board()

Why? When you use Back.RED or Fore.RED, it just changes the global output color (and not just that particular print() statement). That means you must change color for every to-be-printed item if you want them in different colors. That's what I did under print_board().

Since you're printing a 3x3 matrix (or 2D array) along with borders between the elements or items, I had to make use of two loops to print each of them in different colors (as required).

Note: The program works, but I think there is some missing logic since the game only works for 1st player; there is no second player (or even a system player). It's out of the scope for this answer.

Upvotes: 1

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