CODEWITHSUNDEEP
javascriptobjectecmascript-6javascript-objectsdestructuring
Nn Karthik
Nn Karthik

Reputation: 122

Destructuring with default objects for nested object

I have a requirement where I have to take a couple of values from a nested object which when not available, should be taken from a default object. For example consider the following object:

const objToDestructure={
   someVal:3,
   anotherVal:4,
   outerObj:{}
}

If I want to take two field field1 and field2 from outerObj then what I was able to do was

const { someVal,anotherVal,outerObj = {field1:22,field2:33}}=objToDestructure;
const {field1,field2}=outerObj;

Is there anyway this can be shortened even more? I tried to do the following:

const { someVal,anotherVal,outerObj:{field1,field2} = {field1:22,field2:33}}=objToDestructure;

But I got both the values as undefined. Is there any reason why this won't work but the individual assignment does?

Upvotes: 1

Views: 99

Answers (1)

Ori Drori
Ori Drori

Reputation: 191966

Because outerObj exists (it's not undefined) in objToDestructure, setting a default for it won't help in this case. Since it's an object, you can destructure field1 and field2 individually, and set a default for each of them:

Set a default empty object, and add a default value for each field:

const { outerObj:{ field1 = 22, field2 = 33} = {}} = objToDestructure;

Example:

const objToDestructure={
   someVal:3,
   anotherVal:4,
   outerObj:{}
}

const { outerObj: { field1 = 22, field2 = 33} = {}} = objToDestructure

console.log(field1, field2)

Upvotes: 1

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