Reputation: 11
Using Oracle SQL, I need to find the IDs (ICFPROKEYI
) that occur more then once, but have a certain field (ICFFLDC
) only once:
ICFPROKEYI|ICFKAVKEYI|ICFNUMS|ICFFLDC
----------|----------|-------|-----------------------------
2234884| 5887| 0|Farbe.14870
2234884| 5887| 1|Ueberschrift_i_24291101.18563
2234884| 5888| 0|Farbe.14870
2234884| 5889| 0|Farbe.14870
2234884| 5890| 0|Farbe.14870
2234884| 5896| 0|Farbe.14870
In this case, 2234884
, because it appears 6 times but has a value (Ueberschrift_i_24291101.18563
) appear only once
Upvotes: 1
Views: 93
Reputation: 70
I have replicated this on my local, please find the below SQL block and try it yourself
drop table test;
CREATE TABLE test(
ICFPROKEYI INTEGER NOT NULL
,ICFKAVKEYI INTEGER NOT NULL
,ICFNUMS number(1,0) NOT NULL
,ICFFLDC VARCHAR(30) NOT NULL
);
INSERT INTO test(ICFPROKEYI,ICFKAVKEYI,ICFNUMS,ICFFLDC) VALUES (2234884,5887,0,'Farbe.14870');
INSERT INTO test(ICFPROKEYI,ICFKAVKEYI,ICFNUMS,ICFFLDC) VALUES (2234884,5887,1,'Ueberschrift_i_24291101.18563');
INSERT INTO test(ICFPROKEYI,ICFKAVKEYI,ICFNUMS,ICFFLDC) VALUES (2234884,5888,0,'Farbe.14870');
INSERT INTO test(ICFPROKEYI,ICFKAVKEYI,ICFNUMS,ICFFLDC) VALUES (2234884,5889,0,'Farbe.14870');
INSERT INTO test(ICFPROKEYI,ICFKAVKEYI,ICFNUMS,ICFFLDC) VALUES (2234884,5888,0,'Farbe.14870');
INSERT INTO test(ICFPROKEYI,ICFKAVKEYI,ICFNUMS,ICFFLDC) VALUES (2234884,5889,0,'Farbe.14870');
INSERT INTO test(ICFPROKEYI,ICFKAVKEYI,ICFNUMS,ICFFLDC) VALUES (2234885,5890,0,'Farbe.14870');
INSERT INTO test(ICFPROKEYI,ICFKAVKEYI,ICFNUMS,ICFFLDC) VALUES (2234885,5896,0,'Farbe.14870');
Query
SELECT A.ICFPROKEYI FROM (select ICFPROKEYI,ICFFLDC, count(*) AS ICFFLDC_CNT from test
group by ICFPROKEYI,ICFFLDC)A LEFT OUTER JOIN
(select ICFPROKEYI,count(*) as ICFPROKEYI_CNT from test group by ICFPROKEYI)B
ON A.ICFPROKEYI = B.ICFPROKEYI WHERE A.ICFFLDC_CNT = 1AND B.ICFPROKEYI_CNT > 1 ;
Upvotes: 0
Reputation: 35910
You can simply use GROUP BY
with HAVING
(two conditions) as following:
SELECT ICFPROKEYI FROM <yourtable> GROUP BY ICFPROKEYI HAVING COUNT(1) > 1 AND SUM(CASE WHEN ICFFLDC = 'Ueberschrift_i_24291101.18563' THEN 1 END) = 1
-- Update
After @ankit specified that it can be any value(not fixed value - Ueberschrift_i_24291101.18563
), OP can achieve the desired result using following query:
SELECT ICFPROKEYI FROM ( SELECT T.ICFPROKEYI, COUNT(1) OVER( PARTITION BY T.ICFPROKEYI, ICFFLDC ) AS CNT FROM YOURTABLE T ) WHERE CNT = 1
Cheers!!
Upvotes: 0
Reputation: 81
I've tried this with MySQL and might be applicable in oracle as well.
SELECT ICFPROKEYI
FROM <yourtable> WHERE ICFPROKEYI IN
(
SELECT ICFPROKEYI
FROM <yourtable>
GROUP BY ICFPROKEYI
HAVING COUNT(ICFPROKEYI) > 1
)
GROUP BY ICFPROKEYI, ICFFLDC
HAVING cnt(ICFFLDC) = 1
Upvotes: 0
Reputation: 314
Here is the postgres query:
select ICFPROKEYI,ICFFLDC from table group by ICFPROKEYI,ICFFLDC having count(*)=1;
Help yourself to write the oracle equivalent for it.
Upvotes: 0
Reputation: 37472
GROUP BY icfprokeyi
and use HAVING count(*) > 1
to get the icfprokeyi
that appear more than once and GROUP BY icfprokeyi, icffldc
and use HAVING count(*) = 1
to get the icfprokeyi
where the icffldc
doesn't exist in another row with the same icfprokeyi
. Then join both aggregations.
SELECT x1.icfprokeyi
FROM (SELECT t1.icfprokeyi
FROM elbat t1
GROUP BY t1.icfprokeyi
HAVING count(*) > 1) x1
INNER JOIN (SELECT t2.icfprokeyi
FROM elbat t2
GROUP BY t2.icfprokeyi,
t2.icffldc
HAVING count(*) = 1) x2
ON x2.icfprokeyi = x1.icfprokeyi;
Upvotes: 1
Reputation: 3340
You can try this:
select a.ICFPROKEYI from table a join table b
on a.ICFPROKEYI = b.ICFPROKEYI and a.ICFFLDC <> b.ICFFLDC
Upvotes: 1