CODEWITHSUNDEEP
php
ptamzz
ptamzz

Reputation: 9375

php string function to get substring before the last occurrence of a character

$string = "Hello World Again".
echo strrchr($string , ' '); // Gets ' Again'

Now I want to get "Hello World" from the $string [The substring before the last occurrence of a space ' ' ]. How do I get it??

Upvotes: 44

Views: 44801

Answers (11)

mickmackusa
mickmackusa

Reputation: 48073

The most direct, single-function approach is to use preg_replace() to remove the last space and all remaining characters (which logically cannot include any spaces).

This is suitable for a wide range of textual scenarios and is easy to adjust because there are just 3 basic components in the pattern.

- match a space
[^ ]* - match zero or more non-space characters
$ - match the end of the string

If there are no spaces in the input string, then the input string will remain unchanged.

Code: (Demo)

$string = "Hello World Again";
var_export(preg_replace('/ [^ ]*$/', '', $string));
// 'Hello World'

Upvotes: 0

Dwarkesh Soni
Dwarkesh Soni

Reputation: 297

<?php
   $str = "Hello World!";
   echo $str . "<br>";
   echo chop($str,"World!");
   // output - Hello 

?>

Upvotes: -2

R T
R T

Reputation: 4559

strripos — Find the position of the last occurrence of a case-insensitive substring in a string

 $string = "hello world again";
 echo substr($string, 0, strripos($string, ' ')); // Hello world

Upvotes: 6

Maciej Płusa
Maciej Płusa

Reputation: 66

function cutTo($string, $symbol) {
    return substr($string, 0, strpos($string, $symbol));
}

Upvotes: -1

Nick
Nick

Reputation: 1

You could just use:

$string = "Hello World Again";
echo preg_replace('# [^ ]*$', '', $string);

This will work regardless of whether the character occurs in the string or not. It will also work if the last character is a space.

Upvotes: 0

Arvind Bhardwaj
Arvind Bhardwaj

Reputation: 5301

The correct implementation should be:

$string = "Hello World Again";
$pos = strrpos( $string, ' ');
if ($pos !== false) {
    echo substr($string, 0, $pos ); //Hello World
}

Otherwise if the character is not found it will print nothing. See following case:

$string = "Hello World Again";
//prints nothing as : is not found and strrpos returns false.
echo substr($string, 0, strrpos( $string, ':') );

Upvotes: 1

zaf
zaf

Reputation: 23274

One (nice and chilled out) way:

$string = "Hello World Again";
$t1=explode(' ',$string);
array_pop($t1);
$t2=implode(' ',$t1);
print_r($t2);

Other (more tricky) ways:

$result = preg_replace('~\s+\S+$~', '', $string);

or

$result = implode(" ", array_slice(str_word_count($string, 1), 0, -1));

Upvotes: 7

meouw
meouw

Reputation: 42140

$string = "Hello World Again";
echo substr($string, 0, strrpos( $string, ' ') ); //Hello World

If the character isn't found, nothing is echoed

Upvotes: 65

Till
Till

Reputation: 3154

$myString = "Hello World Again";
echo substr($myString, 0, strrpos($myString, " "));

Upvotes: 5

DaveK
DaveK

Reputation: 4607

You can use a combination of strrpos, which gets the position of the last instance of a given string within a string, and substr to return the value.

Upvotes: 1

sdleihssirhc
sdleihssirhc

Reputation: 42496

This is kind of a cheap way to do it, but you could split, pop, and then join to get it done:

$string = 'Hello World Again';
$string = explode(' ', $string);
array_pop($string);
$string = implode(' ', $string);

Upvotes: 13

Related Questions