Reputation: 163
I want to filter objects based on a set of arrays containing filter terms. It basically works until one of the filter arrays contains multiple terms. Here is the code:
// the filters
const filters = {
"eyeColor": ["blue"],
"gender": ["male"],
"age": ["33"],
"tags": ["d3js", "vuejs"] // multiple terms in the filter array breaks the code (returns empty array)
}
// the data
const users = [
{
"age": "33",
"eyeColor": "blue",
"tags": "d3js, max, grotesk",
"gender": "male",
},
{
"age": "31",
"eyeColor": "blue",
"tags": "vuejs, adrian, serif",
"gender": "male",
},
{
"age": "37",
"eyeColor": "brown",
"tags": "vuejs, max, mono, d3js",
"gender": "female",
},
{
"age": "33",
"eyeColor": "blue",
"tags": "vuejs, markus, grotesk",
"gender": "male",
},
]
// the filter function
let results = users.filter(function (object) {
return Object.entries(filters).every(function ([key, value]) {
return value.every(function (filter) {
return object[key].includes(filter)
})
})
});
console.log(results);
I get an empty array, while the expected result would be:
{
"age": "33",
"eyeColor": "blue",
"tags": "d3js, max, grotesk",
"gender": "male",
},
{
"age": "33",
"eyeColor": "blue",
"tags": "vuejs, markus, grotesk",
"gender": "male",
}
How can I get the expected result?
Upvotes: 2
Views: 119
Reputation: 56855
The code uses
return value.every(function (filter) ...
// ^^^^^
but you don't want to match all of the tags in the permitted array, only some
(any):
return value.some(function (filter) ...
// ^^^^
Here's a demonstration:
const filters = { "eyeColor": ["blue"], "gender": ["male"], "age": ["33"], "tags": ["d3js", "vuejs"] }
const users = [{ "age": "33", "eyeColor": "blue", "tags": "d3js, max, grotesk", "gender": "male", }, { "age": "31", "eyeColor": "blue", "tags": "vuejs, adrian, serif", "gender": "male", }, { "age": "37", "eyeColor": "brown", "tags": "vuejs, max, mono, d3js", "gender": "female", }, { "age": "33", "eyeColor": "blue", "tags": "vuejs, markus, grotesk", "gender": "male", }, ];
const filterEntries = Object.entries(filters);
const results = users.filter(user =>
filterEntries.every(([key, permitted]) =>
permitted.some(e => user[key].includes(e))
)
);
console.log(results);
Upvotes: 2