Reputation: 589
I have a very simple formula, but it gives out unwanted result.
=IF(A1>=0,A1,0)
The above formula one gives 0 as TEXT if the if-statement is false for some reason. I did IsNumber() and it returns False. How can this be?
=IF(A1>0,0,A1)
This one gives 0 as a real number in a cell if the if-statement is true referencing the same exact cell A1.
A1 =IF(ISERROR(INDEX('$G$2:$G$80,MATCH($BQ$6,'$B$2:$B$80,0))), "0.000",INDEX('$G$2:$G$80,MATCH($BQ$6,'$B$2:$B$80,0)))
Any help is appreciated.
Upvotes: 1
Views: 4023
Reputation: 2309
Your issue is not with cell A1 being formatted as text, since you have a formula in there calculating the result. The issue is with the formula in cell A1.
=IF(ISERROR(INDEX($G$2:$G$80,MATCH($BQ$6,$B$2:$B$80,0))), "0.000",INDEX($G$2:$G$80,MATCH($BQ$6,$B$2:$B$80,0)))
(This is after cleaning the remnant '
characters, probably from where you removed references to another workbook)
In your formula, the TRUE
return is "0.000"
, since this is in quotes, this is interpreted as text not as a number. If you were to remove the quotes, the formula will auto-correct to 0
only, returning the actual numeric value 0.
If you want this to be formatted as 0.000, don't return "0.000"
but return 0
and format your cell with a numeric format with 3 decimal places.
Upvotes: 1