CODEWITHSUNDEEP
xmlasp.net-mvc-3razor
Ray
Ray

Reputation: 12441

How do I output xml with ASP.NET razor?

Hi I'm trying to return a view that is xml, meaning the content type will be "text/xml", and the view is using ASP.NET MVC razor. Another post ASP.NET MVC and text/xml content type showed how to do it with aspx view. How do I get the same done with razor?

Upvotes: 12

Views: 19638

Answers (4)

Narbs
Narbs

Reputation: 131

A couple things you need to be aware of.

  1. Make sure to set the layout to null or else your output will include the root layout.
  2. Content type needs to be text/xml
  3. Finally, you need to make sure you have no carriage return at the start of the document since XML parsers expect to see the root <?xml element at the beginning. This means your <?xml needs to start right after the closing @{}

Controller

[HttpGet]
public ViewResult SomeXML()
{
    return View();
}

View (SomeXML.cshtml)

@{ 
    Layout = null;
    Response.ContentType = "text/xml";
}<?xml version="1.0" encoding="utf-8" ?>
<element>
   ...
</element>

Upvotes: 1

Darren
Darren

Reputation: 4488

For anyone trying to do this is ASP.NET Core, you can find the Response as a property of the Context:

@{
    Context.Response.ContentType = "text/xml";
}
<?xml version="1.0" encoding="UTF-8" ?>
<doc>
    ...
</doc>

Although I found setting the content type in the Action worked perfectly well (as suggested by @Luis above)

Upvotes: 3

Luis Perez
Luis Perez

Reputation: 28120

If you prefer you can instead make the content type change from your view action, like so:

public ActionResult MyAction() {
    Response.ContentType = "text/xml";
    return View();
}

Upvotes: 8

fretje
fretje

Reputation: 8372

I found an example of an rss feed produced with a razor view here:

writing xml in razor syntax

Basically you have to set the Response.ContentType to "text/xml", and then you can just write your xml as if it was html.

You have to scroll down to see the actual code so I'll copy it here:

@{
    var db = Database.OpenFile("Database.sdf");
    var getRss = db.Query("SELECT TOP(5) * FROM Table" );
    Response.ContentType = "text/xml";
}
<rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:sy="http://purl.org/rss/1.0/modules/syndication/" xmlns:admin="http://webns.net/mvcb/" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:content="http://purl.org/rss/1.0/modules/content/">
    <channel>
        <title>Website name</title>
        <link>website link</link>
        <description>News for website</description>
        <dc:language>en-gb</dc:language>
        <dc:creator>email</dc:creator>
        <dc:rights>Copyright 2010</dc:rights>
        <admin:generatorAgent rdf:resource="http://www.styledna.net/" />
        @foreach (var row in getRss) {
            <item>
                <title>@row.title</title>
                <link>@row.link</link>
                <description> some html desc for the item </description>  
            </item>
        }
    </channel>
</rss>

by Mikesdotnetting

Upvotes: 34

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