Is it possible to get the location of the jlink image when an application is run using the launcher?

Question

For example, here's the outputted jlink image:

├── bin
│   ├── java
│   ├── keytool
│   └── launcher
├── conf
│   ├── net.properties
│   ├── sdp
│   └── security
├── include
│   ├── classfile_constants.h
│   ├── jni.h
│   ├── jvmticmlr.h
│   ├── jvmti.h
│   └── linux
├── legal
│   └── java.base
├── lib
│   ├── classlist
│   ├── jexec
│   ├── jrt-fs.jar
│   ├── jspawnhelper
│   ├── jvm.cfg
│   ├── libjava.so
│   ├── libjimage.so
│   ├── libjli.so
│   ├── libjsig.so
│   ├── libnet.so
│   ├── libnio.so
│   ├── libverify.so
│   ├── libzip.so
│   ├── modules
│   ├── security
│   ├── server
│   └── tzdb.dat
├── man
│   └── man1
└── release

In the bin dir, I have the launcher file which will execute my modular Java application.

My plan is to add more directories such as settings, work etc to the outputted jlink image directory. The users will simply get this image as a zip file, and use the launcher file after unzipping to run my application.

The problem is that I have no idea how to get access to my custom added directories (such as settings, work, etc) since the user could unzip this image anywhere. If I could somehow get the location of this image, everything would work great. Perhaps there is a way to figure out the location of java executable (since it would just be the java executable present in the bin directory) running my program? I'm not sure.

Any suggestions?

Answer 1

For those who reach this question without an answer, use System.getProperty("java.home")