Reputation: 10574
#include < iostream >
#define MY_CHK_DEF(flag) \
#ifdef (flag) \
std::cout<<#flag<<std::endl; \
#else \
std::cout<<#flag<<" ,flag not define"<<std::endl; \
#endif
int main()
{
MY_CHK_DEF(FLAG_1);
MY_CHK_DEF(FLAG_2);
MY_CHK_DEF(FLAG_3);
...
}
complier report:
main.cpp:3:24: error: '#' is not followed by a macro parameter
any ideas?
Thanks
Upvotes: 10
Views: 13411
Reputation: 1678
You actually can do this if you use BOOST processor header lib.. it provides a BOOST_PP_IF macro allow this type of decisions.
http://www.boost.org/doc/libs/1_53_0/libs/preprocessor/doc/ref/if.html
Upvotes: 1
Reputation: 19477
You have to do it the other way round(defining the macro for each #if/#ifdef/#else condition(if you nest you have to put a definition on each branch). You probably should define it at every logical branch or it will fail to compile when you try to adjust a rarely adjusted flag. You can #define noops like this. Note to be careful not to wrap expressions with side effects into #define 'd macros that reduce to a noop when the debug flag is on, or your program may not work right.
#define N(x)
#include < iostream >
#ifdef (flag)
#define MY_CHK_DEF(flag)
std::cout<<#flag<<std::endl;
#else
#define MY_CHK_DEF(flag) \
std::cout<<#flag<<" ,flag not define"<<std::endl;
#endif
int main()
{
MY_CHK_DEF(FLAG_1);
MY_CHK_DEF(FLAG_2);
MY_CHK_DEF(FLAG_3);
...
}
Upvotes: 6
Reputation: 14029
C preprocessor is single-pass and #define creates a pretty dumb replacement that isn't further processed - your MY_CHK_DEF(flag) macro inserts the #if statement inline into preprocessed code that is interpreted by C compiler and not valid C.
You can either rephrase it to be one-pass, or if you can't, run through preprocessor twice, manually - once through cpp -P
and the second time through normal compilation process.
Upvotes: 2
Reputation: 17114
You can't do it. #if, #else, and #endif must be the first tokens on the logical line. Your definition is just one logical line, so it doesn't work,
Upvotes: 8