CODEWITHSUNDEEP
pythonselenium-webdriverweb-scrapingautomationselenium-chromedriver
Varun
Varun

Reputation: 65

No such file in the directory

I am New To Python, I Need to pass a list of URLs as input to the script, I used f1=open to read and f2=open for writing output

from selenium import webdriver
import selenium
import time
import bs4
import sys



f1=open("links.txt","r")
urls=f1.readlines()
urls=[urls.split()[0] for x in urls]
f1.close()

f2=open("a.txt","w")
for url in urls:
    driver = webdriver.Chrome()
    driver.get(url)
    time.sleep(5)
    print(driver.current_url)
    f2.write(str(driver.current_url)+"\n")

f2.close()

But i got this erro

FileNotFoundError: [Errno 2] No such file or directory: 'links.txt'

Please Help Me

Upvotes: 1

Views: 623

Answers (1)

KunduK
KunduK

Reputation: 33384

FileNotFoundError: [Errno 2] No such file or directory: 'links.txt'

The error mentioned that file is not present in the directory.

Please note that you need to check the file name. I believe you have created text file by right click on new text file and then named it as links.txt therefore when you open the file name changed to links.txt.txt just save as this file as mentioned in snapshot.

enter image description here

And try below options.

f1=open("links.txt","r")

Or you could do instead of save as the file as mentioned above.

f1=open("links.txt.txt","r")

Or You can use full path of the file to open the file.

f1=open(r"D:\Foldername\links.txt.txt","r")

OR

f1=open(r"D:\Foldername\links.txt","r")

Let me know if this workaround worked for you.

Upvotes: 1

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