CODEWITHSUNDEEP
phparrays
Fuxi
Fuxi

Reputation: 7599

How to declare an associative array?

I'm wondering if it's possible to define an array of parameters (sorry dunno how it's called) like in jQuery also in PHP:

{myCaption: 'bla', myValue: 123 }

Upvotes: 1

Views: 218

Answers (8)

Rudi Visser
Rudi Visser

Reputation: 21969

The snippet you posted is an object literal (as named a literal form of defining an object), this can also be done more explicitly in Javascript and as mentioned before, jQuery is a framework/library, and not a language.

To define the same array in PHP you would do:

$array = array('myCaption' => 'bla', 'myValue' => 123);

An object literal is almost directly conforment to JSON and as such which minor modifications can be passed through to the json_decode method, allowing you get an array out of this.

It works like this (modifications included):

$js_str = '{"myCaption": "bla", "myValue": "123"}';
$obj = json_decode($js_str, true);

You can also go back the other way like so:

$array = array('myCaption' => 'bla', 'myValue' => 123);
$js_str = json_encode($array);

Upvotes: 0

Kevin
Kevin

Reputation: 5694

You want to create an object? Easy:

$obj = array(
    'key' => 'someValue',
    'anotherKey' => 23
);

Is 'equivalent' to:

var obj = {
    key: 'someValue',
    anotherKey: 23
};

Note however, you are refering to 'as in jQuery'. Don't forget jQuery is just a library!

You could also create class in PHP which holds your values:

class A
{
    public $myValue;

    public function __construct($myValue)
    {
         $this->myValue = $myValue;
    }
}

$obj = new A(23);
echo $obj->myValue; // 23

See the following link for some more information on classes.

Upvotes: 1

Martin Bean
Martin Bean

Reputation: 39389

You have two options: an associative array or an object. A lot of the previous examples show you have to create an array:

$obj = array(
    'key' => 'someValue',
    'foo' => 'bar',
    'baz' => 'somethingElse'
);

Or you can create a true object:

$obj = new stdClass();
$obj->key = 'someValue';
$obj->foo = 'bar';
$obj->baz = 'somethingElse';

Upvotes: 0

shevski
shevski

Reputation: 1022

I think you'll get the same result using in PHP:

$A=array ("myCaption"=>"bla","myValue"=>123);

http://php.net/manual/en/language.types.array.php

you could always take objects in PHP and turn them into JSON

http://php.net/manual/en/function.json-encode.php

and from JSON into PHP with:

http://php.net/manual/en/function.json-decode.php

Upvotes: 3

RobertPitt
RobertPitt

Reputation: 57268

Yes and no, in Javascript this is called a object literal, now it can be created within php but it cannot be used like an array, you can create a object literal using json_encode, for example:

//Create an array
$json = array(
    "myCaption" => 'bla',
    "myValue" => 123
);

//Convert it to a PHP Object
$data = (object)$data;

//Get the results in an json stricg:
$result = json_encode($data);

echo $result;

this should return something along the lines of: {myCaption: 'bla', myValue: 123 }, it amy wrapped in an array thought, not 100% sure but you may get [{myCaption: 'bla', myValue: 123 }] instead.

Upvotes: 0

kkszysiu
kkszysiu

Reputation: 537

Theoretically you can. It's something like JSON syntax so you could do something like that:

var_dump(json_decode("{'myCaption': 'bla', 'myValue': 123 }", true));

But that's ugly way :)

Upvotes: 0

Gaurav
Gaurav

Reputation: 28755

$arry = array('myCaption'=>"bla",'myValue'=>123);

Upvotes: 3

Quentin
Quentin

Reputation: 943216

In JavaScript, it is called an object. jQuery is just a JS library, it isn't a language.

The PHP equivalent is an associative array.

$foo = array( "myCaption" => 'bla', "myValue" => 123 );

Upvotes: 0

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